Hye，我能问一些问题吗。我想使用在数据库中设置的id更新数据库中的数据。数据可以更新，但我希望在更新页面中。数据库中的信息首先被查看，我可以为新的输入删除和更改。编码就在这里。你能告诉我怎么做吗？
<?php
require "cn.php";
$query=mysql_query("select*from medicine");
$num=1;
?>
<!DOCTYPE HTML>
<head>
<style>
body
{
background:url("pharmacy.jpg");
background-size:2000px 1100px;
background-repeat:no repeat;
padding-top:40px;
}
</style>
<title>View Stock</title>
</head>
<table align="center" width="800" border="5" bgcolor="white" bordercolor="red">
<tr>
<td><div align="center"><a href="mainpage.php" >HOME</div></a></td>
<td><div align="center"><a href="stock.php">STOCK</div></a></td>
<td><div align="center"><a href="view.php">REPORT</div></a></td>
<td><div align="center"><a href="staff.php">UPDATE INFORMATION</div></a></td>
</tr>
</table>
<br>
<br>
<br>
<br>
<div align="middle">
<table border="5" bgcolor="white" bordercolor="red">
<tr align="middle">
<td>No</td>
<td>Code</td>
<td>Medicine</td>
<td>Stock</td>
<td>Price</td>
<td colspan="2">action</td>
</tr>
<?php
while($fetch=mysql_fetch_object($query))
{
?>
<tr>
<td><?php echo $num;?></td>
<td> <?php echo $fetch->code;?></td>
<td><?php echo $fetch->medicine;?></td>
<td><?php echo $fetch->stock;?></td>
<td><?php echo $fetch->price;?></td>
<td><a href="update.php?id=<?php echo $fetch->id;?>">update</a></td>
<td><a href="deleteh.php?id=<?php echo $fetch->id;?>">delete</a></td>
</tr>
<?php
$num++;
}
?>
</div>
</table>
</html>
Update.php编码
<?php
if(isset($_GET['id']))
$id=$_GET['id'];
?>
<!DOCTYPE HTML>
<head>
<title>Update stock</title>
<style>
body
{
background:url("pharmacy.jpg");
background-size:2000px 1100px;
background-repeat:no repeat;
padding-top:40px;
}
</style>
</head>
<form Action="updateh.php" method="post">
<table align="center" width="800" border="5" bgcolor="white" bordercolor="red">
<div align="center"><h2>Enter New Update</h2></div>
<tr>
<td align="center" colspan=4>Name</td>
</tr>
<br>
<div align="right">
<a href="view.php"><font color="white">Back to Stock Update</a></font><br>
</div>
<tr>
<td><div align="center">Code</div></td>
<td><div align="center">Medicine</div></td>
<td><div align="center">Stock</div></td>
<td><div align="center">Price(RM)</div></td>
</tr>
<tr>
<td><div align="middle"><input type="textbox" name="code" required></div></td>
<td><div align="middle"><input type="textbox" name="medicine" required></div></td>
<td><div align="middle"><input type="textbox" name="stock" required></div></td>
<td><div align="middle"><input type="textbox" name="price" required></div></td>
</tr>
<tr>
<td align="middle" colspan=4><input type="submit" value="update">
<input type="hidden" name="id" value="<?php echo $id;?>">
</td>
</tr>
</table>
</Form>
</html>
updateh.php编码
<?php
session_start();
require "cn.php";
$id=$_POST['id'];
$code=$_POST['code'];
$medicine=$_POST['medicine'];
$stock=$_POST['stock'];
$price=$_POST['price'];
mysql_query("update medicine set code='$code', medicine='$medicine', stock='$stock',
price='$price' where id='$id'");
echo header("location: sucess2.php");
?>
if(isset($_POST['submit'])) {
$code= $_POST['code'];
$medicine= $_POST['medicine'];
$stock= $_POST['stock'];
$price= $_POST['price'];
$sql= mysql_query(UPDATE `your_table` SET `code`,`medicine`,`stock`,`price`) VALUES ('$code','$medicine','stock','$price') WHERE `id`='$id';
}
使用此项，然后读取并使用mysqli而不是mysql