使用ajax将一个子表单嵌入到另一个子表单中

我知道symfony 1.4 Form系统不是最好的，给很多人带来了很多麻烦，但是我需要完成这个任务，我需要帮助。

我需要将子表单嵌入到嵌入在主表单中的子表单中，并通过Ajax实现。

基本上我有aForm, bForm和cForm和aForm嵌入bForm和bForm可以有一个或多个cForm。

当我嵌入他们通常从配置()函数的每个形式它的工作原理。但是当我尝试使用Ajax将多个cform嵌入到bForm中时，我无法绑定它们。

这是有效的版本。一切都是嵌入ok和验证ok。

class BookingForm extends BaseBookingForm
{
  public function configure()
  {     
      $this->embedRelation('Journey as journey');
  }
}
[...]
class JourneyForm extends BaseJourneyForm
{
  public function configure()
  {
      $pickup_form = new JourneyItineraryForm();
      $this->embedForm('pickup_form', $pickup_form);
  }
} 
[...]
class JourneyItineraryForm extends BaseJourneyItineraryForm
{
  public function configure()
  {
  }
}
[...]

现在，如果我尝试通过ajax嵌入JourneyItineraryForm，我设法在模板中显示小部件，但它无法绑定它们。它告诉我意外的额外表单字段名为"waypoint"

查看下面代码:

class JourneyForm extends BaseJourneyForm
{
      public function configure()
      {
          $waypoint_form = new JourneyItineraryForm();
          $this->embedForm('waypoint', $waypoint_form);
      }
      public function addNewWaypoint($number)
      {
       /*
       * Called from actions.class.php after an ajax request
       */
       $new_waypoints = new BaseForm();
       for($i=0; $i <= $number; $i+=1)
       {
         $waypoint = new JourneyItinerary();
         $waypoint_form = new JourneyItineraryForm($waypoint);
         $new_waypoints->embedForm($i,$waypoint_form);
       }
      $this->embedForm('waypoint', $new_waypoints);
      }
    public function bind(array $taintedValues = null, array $taintedFiles = null)
    {
      $new_occurrences = new BaseForm();
      foreach($taintedValues['waypoint'] as $key => $new_occurrence)
      {
        $occurrence = new JourneyItinerary();      
        $occurrence_form = new JourneyItineraryForm($occurrence);
        $new_occurrences->embedForm($key,$occurrence_form);
      }
      $this->embedForm('waypoint',$new_occurrences);
      parent::bind($taintedValues, $taintedFiles);
    }
 } 

在我的模板中，我设法显示像

这样的路点小部件

$form['journey']['waypoint'][0]['field_name']->renderRow();

我还试图覆盖BookingForm的bind方法，但我不知道我是否做对了:

public function bind(array $taintedValues = null, array $taintedFiles = null)
{   
    $new_occurrences = new sfForm();
    foreach($taintedValues['journey']['waypoint'] as $key => $new_occurrence)
    {
      $occurrence = new JourneyItinerary();      
      $occurrence_form = new JourneyItineraryForm($occurrence);
      $new_occurrences->embedForm($key,$occurrence_form);
    }
    $this->embedForm('journey',$new_occurrences);
    parent::bind($taintedValues, $taintedFiles);
}

我遵循这个教程:http://tech.cibul.net/embedded-forms-with-symfony-1-4-and-jquery/并阅读官方文档http://symfony.com/legacy/doc/more-with-symfony/1_4/en/06-Advanced-Forms

任何帮助都非常感谢:)谢谢。