PHP:迭代另一个函数的结果和输出的函数 - PHP: Function to iterate results from another function and output

PHP: Function to iterate results from another function and output

似乎这将是相当简单，然而，我遇到了一个问题:

代码如下:

function getValidCustomers() {
    global $db;
    $getCustomers = $db->GetAll("SELECT * from customers where CustomerActive='1' AND protected IS NULL or protected=0;");
    foreach($getCustomers as $customer) {
        echo $customer['CustomerID']."'n";
    }
}
function updateValidCustomers() {
    $customers = getValidCustomers();
    for ($i = 0; $i < sizeof($customers); $i++) {
        echo "DEBUG: $customers[$i]'n";
    }
}
updateValidCustomers();

基本上，现在的输出是customerid的列表(来自updateValidCustomers())。我只想让updateValidCustomers()从getValidCustomers()获取数据，然后循环它，这样我就可以在它上运行另一个查询，这将实际操作数据库。

任何想法?

getValidCustomers不返回任何东西，也许你的意思是:

function getValidCustomers() {
    global $db;
    $getCustomers = $db->GetAll("SELECT * from customers where CustomerActive='1' AND protected IS NULL or protected=0;");
    foreach($getCustomers as $customer) {
        echo $customer['CustomerID']."'n";
    }
    return $getCustomers;
}

getValidCustomers()不返回任何东西-它只是回显

将return $getCustomers添加到getValidCustomers()的末尾

添加return $getCustomers;到getValidCustomers():D