我试图从android请求到PHP文件。之后,我需要将PHP(单个代码)生成的响应保存到一个文件中,这样我就可以下次读取它,而不必再次发出请求。对于请求,我创建了一个新方法,如下所示:
> private String deviceIdHttpGetter(){
> HttpHandler handler = new HttpHandler();
> String code=handler.post("http://www.cafegourmet.es/newUser.php");
> Toast.makeText(getApplicationContext(), "your code is " + code, Toast.LENGTH_SHORT).show();
> return code;
>
> }
我还修改了HttpHandler post()方法,以便我可以获得代码并返回它,所以现在它看起来像这样:
> public String post(String postURL){
> try {
> HttpClient client = new DefaultHttpClient();
> HttpPost post = new HttpPost(postURL);
> HttpResponse response = client.execute(post);
> HttpEntity ent = response.getEntity();
> String text = EntityUtils.toString(ent);
> return text;
> }
>
> catch(Exception e) { return e.getMessage();}
> }
现在PHP的内容如下:
<?php $code = 12345; echo $code; ?>
嗯…问题是,我不知道为什么,但我总是看到吐司好像没有收到代码("你的代码是"),但是当我从资源管理器访问这个PHP时,我总是得到我需要的新代码,因此我不能将数据保存到文件。
有什么建议吗?提前感谢大家
下面是解决问题的代码,希望对大家有所帮助:
首先,在主活动中调用async的代码如下所示:private String deviceIdHttpGetter(){
try
{
AsyncHttpDeviceId asyncId = new AsyncHttpDeviceId();
return asyncId.execute("http://www.cafegourmet.es/newUser.php").get();
}
catch(Exception e){
return e.toString();
}
}
}
Async最后的读取如下:
public class AsyncHttpDeviceId extends AsyncTask<String, Integer, String> {
String code="";
public AsyncHttpDeviceId () {
}
/**
* background
*/
protected String doInBackground(String... posturl ) {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response;
String responseString = null;
try {
response = httpclient.execute(new HttpGet(posturl[0]));
StatusLine statusLine = response.getStatusLine();
if(statusLine.getStatusCode() == HttpStatus.SC_OK){
ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
responseString = out.toString();
out.close();
} else{
//Closes the connection.
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
return e.toString();
} catch (IOException e) {
return e.getMessage();
}
return responseString;
}
protected void onPostExecute(String result) {
code=result;
}
}
希望有一天能帮到别人。