Ajax不起作用-无论如何都发布了修复的PHP


Ajax not working - posted fixed PHP anyway

Html:

<form action="registerusers.php" method="POST">
    <input id= "uname" name="uname" placeholder="username" required>
    <input id="upassword" name="upassword" type="password"   placeholder="password" required>
    <button id="register" type="button" class="btn btn-primary btn-lg outline" onclick="javascript: validateForm();checkNameRegister();" >Register</button>

Ajax:

function checkNameRegister() {
$.ajax({
          url: "registerusers.php",
          data: { uname : "uname" , upassword : "upassword"},
          type: "POST",
          async: false,
          dataType: 'text',
          success: function(responseText) {
            alert(responseText);
          }
    });

};

php:

<?php

header('Content-Type:application/json'(;

error_reporting(E_ALL);
ini_set('display_errors', 1);
$alert1 = null;
$uname = filter_input(INPUT_POST, isset($_POST['uname'])); 
if ($uname === $_POST['uname'] ? $_POST['uname'] : ''){
try {
$conn = new PDO('mysql:host=127.0.0.1;dbname=users', 'root', 'redcardinal');
$conn->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$query = 'SELECT * FROM `usernames` WHERE `uname` = :uname';
$stmt = $conn->prepare($query);
$stmt->bindParam(":uname",$uname, PDO::PARAM_STR, strlen($uname));

$stmt->execute();
$hello = array(array());
if ($hello = $stmt->fetch(PDO::FETCH_ASSOC) ? $hello != null : ''){
    $alert1 = "This name is taken.";
echo json_encode($alert1);
$conn = null;
$query = null;
}
elseif ($hello === null) {
    $alert2 = "This name is not taken.";
 echo json_encode($alert2);
}
}
catch (PDOException $e) { echo json_encode($e);
$conn = null;
$query = null;
}
EDIT: WILL PUT ADDITIONAL elseif HERE.
}
?>
<?php 

header('Content-Type:application/json'(;

error_reporting(E_ALL); 
ini_set('display_errors', 1); 
include 'check_name.php'; 
$uname = filter_input(INPUT_POST, isset($_POST['uname'])); 
if ($uname != null && $alert1 === null) { 
try {
$conn = new PDO  ('mysql:host=127.0.0.1;dbname=users', 'root', 'redcardinal'); 
$conn->setAttribute(PDO::ATTR_EMULATE_PREPARES, false); 
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
$uname = $_POST['uname']; 
$upassword = password_hash(filter_input(INPUT_POST, isset($_POST['upassword'])), PASSWORD_DEFAULT); 

$stmt = 'INSERT INTO `usernames` (`uname`, `upassword`) VALUES (:uname,:upassword)'; 
$query = $conn->prepare($stmt); 
$query->bindParam(":uname",$uname, PDO::PARAM_STR, strlen($uname)); 
$query->bindParam(":upassword",$upassword, PDO::PARAM_STR, strlen($upassword)); 

$query->execute(); 
echo json_encode("Username/Password successfully created.");
} 
catch (PDOException $e) {
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
}
elseif ($alert1 != null) { 
echo json_encode("Username/Password taken."); 
}
$query = null; 
$conn =null; 

我基本上按照建议更改了PHP,唯一能想到的其他问题是html或ajax。感谢

您有if ($hello = null) {

您需要将其更改为if ($hello === null) {

<?php
header('Content-Type: application/json');

error_reporting(E_ALL);
ini_set('display_errors', 1);
$alert1 = null;
if ($uname = isset($_POST['uname']) ? isset($_POST['uname']) : ''){
try {
$conn = new PDO('mysql:host=127.0.0.1;dbname=users', 'root', 'password');
$conn->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$query = 'SELECT * FROM `usernames` WHERE `uname` = :uname';
$stmt = $conn->prepare($query);
$stmt->bindParam(":uname",$uname, PDO::PARAM_STR, strlen($uname));

$stmt->execute();
$hello = array(array());
if ($hello = $stmt->fetch(PDO::FETCH_ASSOC) && $hello != null){
    $alert1 = "This name is taken.";
echo json_encode($alert1);
$conn = null;
$query = null;
}
if ($hello === null) {
    $alert1 = "This name is not taken.";
 echo json_encode($alert1);
}
}
catch (PDOException $e) { echo json_encode($e);
$conn = null;
$query = null;
$alert1 = null;
}

 }

关于第二个问题,有两件事是错误的。

  1. if ($uname != null && $alert1 = null) {更改为if ($uname != null && $alert1 === null) {,您需要将1=改为三个===。

  2. 再次将else ($alert1 != null) {更改为elseif ($alert1 != null) {,然后再做一个if语句,所以需要做esleif而不是else。

    error_reporting(E_ALL(;ini_set('display_errors',1(;包括"check_name.php";

    $uname=filter_input(input_POST,isset($_POST['uname']((;

    if($uname!=null&&$alert1===null({尝试{$conn=新PDO('mysql:host=127.0.0.1;dbname=users','root','password'(;$conn->setAttribute(PDO::ATTR_EMULATE_REPREPARES,false(;$conn->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION(;

    $uname=$_POST['uname'];

    $upassword=password_hash($_POST['upassword'],password_DEFAULT(;

    $stmt='插入usernames(unameupassword(值(:uname,:upassword(';$query=$conn->prepare($stmt(;$query->bindParam(":uname",$uname,PDO::PARAM_STR,strlen($uname((;$query->bindParam(":upassword",$upassword,PDO::PARAM_STR,strlen($upassword((;

    $query->execute((;}catch(PDOException$e({打印"错误!:"$e->getMessage((。">
    ";die((;}}elseif($alert1!=null({

    echo json_encode("此名称已被使用,请选择其他名称。"(;}

    $query=null;$conn=null;

    ?>