Preg_match与第一个实例匹配 - preg_match with first instance

我试图在字符串内部的单词"in"answers"with"之间抓取一个单词。问题是我有另一个"with"的实例，它将扩展通配符。

下面是一个例子:

$item   = 'This is a car in red with new tires and with a radio';
$pattern =  = '/in (.*) with/i';
preg_match($pattern, $item, $matches);

的回报:

array(2) {
  [0]=>
  string(30) "in red with new tires and with"
  [1]=>
  string(22) "red with new tires and"
}

我希望$matches[1]是'red'

将样式改为:

$pattern  = '/in ([^'s]*)(.*) with/i';
// Array ( [0] => in red with new tires and with [1] => red [2] => with new tires and )

其中([^'s]*)表示-取除space以外的所有符号