将自定义参数传递给Symfony2中的自定义ValidationConstraint - Pass custom parameters to custom ValidationConstraint in Symfony2

我正在Symfony2中创建一个表单。表单只包含一个book字段，它允许用户在Books实体列表中进行选择。我需要检查所选的Book是否属于我控制器中的Author。

public class MyFormType extends AbstractType
{
    protected $author;
    public function __construct(Author $author) {
        $this->author = $author;
    }
    public function buildForm(FormBuilderInterface $builder, array $options) {
        $builder->add('book', 'entity', array('class' => 'AcmeDemoBundle:Book', 'field' => 'title');
    }
    // ...
}

我想检查，提交表单后，选定的Book是由$author在我的控制器:

public class MyController
{
    public function doStuffAction() {
        $author = ...;
        $form = $this->createForm(new MyFormType($author));
        $form->bind($this->getRequest());
        // ...
    }
}

不幸的是，我找不到任何方法来做这件事。我尝试创建一个自定义的验证器约束，正如在The Cookbook中所解释的，但是当我可以通过将验证器定义为服务来传递EntityManager作为参数时，我不能将$author从控制器传递到验证器约束。

class HasValidAuthorConstraintValidator extends ConstraintValidator
{
    private $entityManager;
    public function __construct(EntityManager $entityManager) {
        $this->entityManager = $entityManager;
    }
    public function validate($value, Constraint $constraint) {
        $book = $this->entityManager->getRepository('book')->findOneById($value);
        $author = ...; // That's the data I'm missing
        if(!$book->belongsTo($author))
        {
            $this->context->addViolation(...);
        }
    }
}

这个解决方案可以是我正在寻找的那个，但是我的表单不绑定到一个实体，也不意味着是(我从getData()方法获得数据)。

我的问题有解决办法吗?这一定是很常见的情况，但我真的不知道如何解决。

在Cerad的帮助下，我终于弄明白了。要注入需要从ConstraintValidator::validate()方法访问的自定义参数，您需要在Constraint中将它们作为选项传递。

public class HasValidAuthorConstraint extends Constraint
{
    protected $author;
    public function __construct($options)
    {
        if($options['author'] and $options['author'] instanceof Author)
        {
            $this->author = $options['author'];
        }
        else
        {
            throw new MissingOptionException("...");
        }
    }
    public function getAuthor()
    {
        return $this->author;
    }
}

并且，在ConstraintValidator中:

class HasValidAuthorConstraintValidator extends ConstraintValidator
{
    private $entityManager;
    public function __construct(EntityManager $entityManager) {
        $this->entityManager = $entityManager;
    }
    public function validate($value, Constraint $constraint) {
        $book = $this->entityManager->getRepository('book')->findOneById($value);
        $author = $this->constraint->getAuthor();
        if(!$book->isAuthor($author))
        {
            $this->context->addViolation(...);
        }
    }
}

最后但同样重要的是，您必须将参数传递给Validator:

public function buildForm(FormBuilderInterface $builder, array $options) {
    $builder->add('book', 'entity', array(
        'class' => 'AcmeDemoBundle:Book',
        'field' => 'title',
        'constraints' => array(
            new HasValidAuthorConstraint(array(
                'author' => $this->author
            ))
        )
    ));
}

首先向约束添加setAuthor方法，然后调整validate方法。接下来的诀窍是确定最好的称呼。

不清楚您是如何将验证器绑定到您的书的。你在使用验证吗?还是在表单内部做一些事情?

嗯，我对Form/Validation组件不是很熟悉，但是你可以使用一个包含作者姓名/id的Hidden字段，并检查它是否相同:

class MyFormType extends AbstractType
{
    protected $author;
    public function __construct(Author $author) {
        $this->author = $author;
    }
    public function buildForm(FormBuilderInterface $builder, array $options) {
        $builder
            ->add('book', 'entity', array('class' => 'AcmeDemoBundle:Book', 'field' => 'title');
            ->add('author_name', 'hidden', array(
                'data' => $this->author->getId(),
            ))
        ;
    }
    // ...
}

接受的答案不适合我使用Symfony框架版本2.1。我就是这样解决的。

class CustomConstraint extends Constraint
{
    public $dependency;
    public $message = 'The error message.';
}
class CustomConstraintValidator extends ConstraintValidator
{
    public function validate($value, Constraint $constraint)
    {
        if (!$constraint->dependency->allows($value)) {
            $this->context->addViolation($constraint->message);
        }
    }
}
class CustomFormType extends AbstractType
{
    private $dependency;
    public function __construct(Dependency $dependency)
    {
        $this->dependency = $dependency;
    }
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('field', 'type', array(
                'constraints' => array(
                    new CustomConstraint(array('dependency' => $this->dependency))
                )
        ));
    }
}