我试图发送电子邮件给用户，我选择使用复选框从相同的index.php页面。我在这里尝试一些东西，但我不知道如何转移和保持检查电子邮件到"密件"领域。这里，是我的代码，请看看!
email的Php代码(index.php):
<?php
if (isset($_POST['submit']))
{
$name = $_POST['name'];
$email = $_POST['email'];
$subject = $_POST['subject'];
$comments = $_POST['comments'];
$to = "";
$headers = "From:$name<$email>";
$headers .= "MIME-Version: 1.0'r'n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1'r'n";
$headers .= "Bcc: $selectedemailsall'r'n";
$message = "Name: $name'n'n Email: $email 'n'n Subject : $subject 'n'n Message : $comments";
if(mail($to,$subject,$message,$headers))
{
echo "Email Send";
}
else
{
echo "Error : Please Try Again !";
}
}
?>
form (index.php)代码:
<!DOCTYPE html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Mail Document</title>
</head>
<body>
<form action="" method="post" >
<p>Name :<br>
<input type="text" name="name" id=""></p>
<p>Email :<br>
<input type="text" name="email" id=""></p>
<p>Subject :<br>
<input type="text" name="subject" id=""></p>
<p>Comments :<br>
<textarea name="comments" id="" cols="30" rows="10"></textarea></p>
<p><input type="submit" value="Send Email" name="SubmitEmail"></p>
</form>
<form action="#" method="post">
<?php
error_reporting(E_ERROR | E_PARSE);
$connection = mysqli_connect("localhost","root", "");
$db = mysqli_select_db("testdb", $connection);
$query = mysqli_query("select * from users", $connection);
while ($row = mysqli_fetch_array($query))
{
echo "
<input type='checkbox' name='check_list[]' value='{$row['email']}'>
<label>{$row['username']}</label><br/>
";
}
?>
<?php
if(isset($_POST['submituserchk']))
{
//to run PHP script on submit
if(!empty($_POST['check_list']))
{
// Loop to store and display values of individual checked checkbox.
foreach($_POST['check_list'] as $selectedemails)
{
$selectedemailsall = $selectedemails.",";
//echo $selectedemailsall;
}
}
}
?>
</div> <!-- End of RightUsersDivWithCheckBox -->
<input type="submit" name="submituserchk" style="margin-left: 87%; margin-top: 20px;" value="Done"/>
</form>
</body>
</html>
有什么解决办法吗?现在，当我点击"完成"并提交电子邮件时，什么都没有发生，我不想在选择电子邮件后点击"完成"按钮。我只是选择电子邮件，它们会在一个变量中转到"密件"字段
不要对很多用户使用密件头。
表单:
...
<input type="checkbox" name="email[]" value="foo@host.tld"> - foo@host.tld
<input type="checkbox" name="email[]" value="bar@host.tld"> - bar@host.tld
<input type="checkbox" name="email[]" value="baz@host.tld"> - baz@host.tld
...
你的后端代码:
...
if (array_key_exists('email', $_POST) && is_array($_POST['email'])) {
foreach ($_POST['email'] as $to) {
mail($to, $subject, $message, $headers);
}
}
...
为所有收件人单独发送的所有电子邮件。对于您的应用程序来说，这是一个灵活的案例——您可以检查每个发送状态。
我终于得到了自己问题的答案。下面是我的代码
显示用户名，电子邮件和复选框从数据库:
$getemail = mysqli_query("SELECT * FROM users",$connection);
if(!$getemail) die('MsSQL Error: ' . mysqli_error());
echo '<div class="AllUserDiv" style="overflow-y:scroll;height:400px;"><table class="table table-bordered">';
echo "<thead>
<tr>
<th><input type='checkbox' onchange='checkedbox(this)' name='chk' /> </th>
<th>Username</th>
<th>Email</th>
</tr>
</thead>";
if(mysqli_num_rows($getemail) == 0)
{
echo "<tbody><tr><td colspan='3'> No Data Available</td></tr></tbody>";
}
while($row = mysqli_fetch_assoc($getemail))
{
echo "<tbody><tr><td><input value='".$row['email']."' type='checkbox' name='check[]' checked /> </td>";
echo "<td>".$row['username']."</td>";
echo "<td>".$row['email']."</td></tr></tbody>";
}
Email Form:
<form method="post" action="">
<p style="margin-top:30px;">Email Subject: <input type="text" name="subject" value="" class="form-control" /></p>
<p>Email Content: <textarea name="message" cols="40" rows="6" style="width:100%;"></textarea></p>
<center><input type="submit" name="submit" value="Send Email Now" class="btn btn-primary btn-block" />
</form>
选择复选框的JavaScript代码:
<script type="text/javascript" language="javascript">
function checkedbox(element)
{
var checkboxes = document.getElementById('input');
if(element.checked)
{
for (var i = 0; i < checkboxes.length; i++ )
{
if(checkboxes[i].type == 'checkbox')
{
checkboxes[i].checked = true;
}
}
}
else
{
for (var i = 0; i < checkboxes.length; i++)
{
console.log(i)
if(checkboxes[i].type == 'checkbox')
{
checkboxes[i].checked = false;
}
}
}
}
</script>