PHP PDO + Sqlite，显示表的索引

我正在尝试使用sqlite和PHP显示表上的索引。

此手册(https://www.sqlite.org/cli.html)建议:

.indexes ?TABLE?

使用

$pdo->query('.indexes my_table');

节目:

PDOException: SQLSTATE[HY000]: General error: 1 near ".": syntax error

是否可以使用PHP和PDO来执行这些点命令?

    $this->pdo->query('DROP TABLE IF EXISTS test');
    $this->pdo->query('CREATE TABLE test (id INT PRIMARY KEY NOT NULL, col1 text NOT NULL, col2 text NOT NULL)');
    $this->pdo->query('CREATE INDEX col1 ON test (col1)');
    $result = $this->pdo->query('PRAGMA table_info(test);')->fetchAll('PDO::FETCH_OBJ);
    print_r($result);

不显示索引。以下错误:

    $this->pdo->query('DROP TABLE IF EXISTS test');
    $this->pdo->query('CREATE TABLE test (id INT PRIMARY KEY NOT NULL, col1 text NOT NULL, col2 text NOT NULL)');
    $this->pdo->query('CREATE INDEX col1 ON test (col1)');
    $result = $this->pdo->query('.indexes test')->fetchAll('PDO::FETCH_OBJ);
    print_r($result);

返回一个空数组:

    $this->pdo->query('DROP TABLE IF EXISTS test');
    $this->pdo->query('CREATE TABLE test (id INT PRIMARY KEY NOT NULL, col1 text NOT NULL, col2 text NOT NULL)');
    $this->pdo->query('CREATE INDEX index_col1 ON test (col1)');
    $result = $this->pdo->query('PRAGMA index_info(test);')->fetchAll('PDO::FETCH_OBJ);
    print_r($result);