Preg_replace用标记之间的空格替换破折号 - Preg_replace replace dashes with spaces between tags

Preg_replace replace dashes with spaces between tags

我有一个HTML代码，并希望仅用空格替换破折号，但仅在特定标记之间。

function getTextBetweenTags($string, $tagname) {
 $pattern = "/<$tagname ?.*>('d*)[-*]('d*)<'/$tagname>/";
 $replace = " ";
 $string = preg_replace($pattern, $replace, $string);
}

代码示例:

<div class="xxx">
<a href="/start">start</a>
<a href="/start/world">World</a>
<a href="/start/world/fantastic-yyy-zz">Fantastic-yyy-zz</a>
  peter-hey
</div>

结果:虽然'peter hey'没有破折号，但更重要的是标签的值。

<div class="xxx">
<a href="/start">start</a>
<a href="/start/world">World</a>
<a href="/start/world/fantastic-yyy-zz">Fantastic yyy zz</a>
  peter-hey
</div>

您不需要正则表达式来执行此任务:

$contents = '<div class="xxx">
<a href="/start">start</a>
<a href="/start/world">World</a>
<a href="/start/world/fantastic-yyy-zz">Fantastic-yyy-zz</a>
  peter-hey
</div>';
$doc = new DOMDocument();
$doc->loadXML($contents);
$tagName = 'a';
$tags = $doc->getElementsByTagName($tagName);
foreach ($tags as $tag) {
    $newValue = str_replace('-', ' ', $tag->nodeValue);
    $tag->nodeValue = $newValue;
}
echo $doc->saveHTML();

演示:http://ideone.com/rI6k8b

@zerkms感谢您的帮助和耐心，几乎完全按照您所说的进行了尝试，但它显示了警告并且没有做出更改。

Warning: DOMDocument::loadXML(): Extra content at the end of the document in Entity

代码:

function process(&$vars) {
  $theme = get_theme();
  if ($vars['elts']['#xxx'] == 'main') {
    $vars['bread'] = $theme->page['bread'];
    /*add code*/
    $doc = new DOMDocument();
    $doc->loadXML($vars['bread']);
    $tagName = 'a';
    $tags = $doc->getElementsByTagName($tagName);
    foreach ($tags as $tag) {
        $newValue = str_replace('-', ' ', $tag->nodeValue);
        $tag->nodeValue = $newValue;
    }
    echo $doc->saveHTML();
    /*end add code*/
  }
}

@zerkms，我给你的答案和你真正给出的正确答案一样有效。我也很惊讶地说，我发现了一些有趣的答案:

代码查找信息

$tagname = 'a';
$pattern = "/<$tagname ?.*>(.*)'-+(.*)<'/$tagname>/";
$matches = "";
preg_match($pattern, $contents, $matches);

CODE TO CHANGE:因为我只有一段代码，所以我真的不需要检查标签是否为'a'。

$pattern = "/>(.*)'-+(.*)'-+(.*)</";
$replace = ">$1 $2 $3<";
$res = preg_replace($pattern, $replace, $contents);

//$contents是包含代码的字符串。

希望它真的能帮助到一些人。