按天分组查询的数据和布局到一个网格


Group by day queried data and lay out to a grid

我有一个有点像社交网络的日志项目,让用户输入他们一整天所做的任何活动。

在我的数据库上,我有一个'日志'表,其中有以下字段:

| log_id | log_content | log_date | log_author |

我的问题是,我怎么能做一个查询,将获取前n天,然后在网格视图中显示其结果,像这样:

| Monday, December 7, 2013
| log_content, log_author, 6 AM | log_content, log_author, 8:30 AM | ...|
| Tuesday, December 8, 2013
| log_content, log_author, 7:10 AM | log_content, log_author, 12:00 NN | log...|
| Wednesday, December 9, 2013
| log_content, log_author, 6:30 PM |
| Thursday, December 10, 2013
| log_content, log_author, 9:53 AM | log_content, log_author, 4:02 PM | ...|
| Friday, December 11, 2013
| log_content, log_author, 1:34 PM |

我知道我不能对整个'logs'表进行查询,因为当日志增长时会导致瓶颈。我正在考虑做一个比特查询,当用户向下滚动时,另一个后台查询将运行下一组要显示的数据(使用限制和偏移)。

目前我的查询是这样的:

function fetch_logs($group_id, $limit, $offset){
        $this->db->select('l.log_id, l.log_date, l.log_content, u.username');
        $this->db->from('logs AS l');
        $this->db->join('log_group_ref AS r', 'l.log_id = r.log_id');
        $this->db->join('users AS u', 'l.log_author = u.user_id');
        $this->db->where('r.group_id', $group_id);
        $this->db->limit($limit, $offset);
        return $this->db->get()->result_array();
    }

但是我不知道如何将查询的数据按天分组,并将它们放入网格中。

我使用Twitter的Bootstrap与网格,所以我可以把每个日志放到一个网格中,然后添加滚动条,如果有更多的日志。

更新:

所以我根据raheel shan的第二种方法更新了我的代码,但我似乎无法得到我想要的数据,直到我添加:

$this->db->group_by(l.log_date);

基于Exander的代码,获取正确的数据集,尽管格式与raheel shan的不同。

在这两个查询中,这是我更新的查询:

$select =   array(
                            "DATE_FORMAT(l.log_date,'%a , %b %d , %Y') AS LogDate",
                            "GROUP_CONCAT(l.log_id) AS LogIDs",
                            "GROUP_CONCAT(l.log_content) AS LogContents",
                            "GROUP_CONCAT(u.username) AS LogAuthors",
                            "GROUP_CONCAT(DATE_FORMAT(l.log_date,'%h:%i %p')) AS LogTimes"
                        );
            $this->db->select($select);
            $this->db->from('logs AS l');
            $this->db->join('log_group_ref AS r', 'l.log_id = r.log_id');
            $this->db->join('users AS u', 'l.log_author = u.user_id');
            $this->db->where('r.group_id', $group_id);
            $this->db->group_by('l.log_date');
            $this->db->limit($limit, $offset);
            return $this->db->get()->result_array();

现在,我将不得不处理每个LogContents, LogAuthors, LogTimes并将它们分组回数组。我需要重新研究一下raheel shan的代码。

更新:我终于得到了实现这一目标所需的所有东西。因为我只能接受一个,所以我会把raheel shan的标记为接受。虽然Exander's也是正确的,加上更少的代码,使它更棒。

我不完全确定,但这个查询似乎能够得到结果,你需要没有任何子查询:

SELECT
    DATE_FORMAT(l.log_date,'%W , %M %d , %Y') AS day,
    GROUP_CONCAT(l.log_content, ', ', u.username, ', ', DATE_FORMAT(l.log_date, '%l:%i %p') ORDER BY l.log_date SEPARATOR ' | ') AS activity
FROM logs as l
INNER JOIN users u ON u.user_id = l.log_author
INNER JOIN log_group_ref r ON r.log_id = l.log_id
WHERE r.group_id = **<YOUR_GROUP_ID>**
GROUP BY DATE(l.log_date) ASC;

您可以在这里看到示例(部分从raheel shan的示例中复制和粘贴)。

您可以这样做。查看Demo

Here

SELECT
    DATE_FORMAT(l.log_date,'%a , %b %d , %Y') as LogDate,
    DATE(l.log_date) as LDate,
    GROUP_CONCAT(r.data) as LogData
FROM logs as l
INNER JOIN  (
            SELECT 
                    logs.log_date,
                    GROUP_CONCAT(other) as data     
            FROM logs
            LEFT JOIN (
                        SELECT 
                            log_date,
                            CONCAT(log_content, ' | ', log_author , ' | ' , DATE_FORMAT(log_date,'%h:%i %p')) as other 
                        FROM logs
                        GROUP BY log_date
            ) as t ON t.log_date = logs.log_date
            GROUP BY log_date
) as r ON r.log_date = l.log_date
GROUP BY LDate

和Codeigniter

$query  ="  SELECT
                DATE_FORMAT(l.log_date,'%a , %b %d , %Y') as LogDate,
                DATE(l.log_date) as LDate,
                GROUP_CONCAT(r.data) as LogData
            FROM logs as l
            INNER JOIN  (
                        SELECT 
                                logs.log_date,
                                GROUP_CONCAT(other) as data     
                        FROM logs
                        LEFT JOIN (
                                    SELECT 
                                        log_date,
                                        CONCAT(log_content, ' | ', log_author , ' | ' , DATE_FORMAT(log_date,'%h:%i %p')) as other 
                                    FROM logs
                                    GROUP BY log_date
                        ) as t ON t.log_date = logs.log_date
                        GROUP BY log_date
            ) as r ON r.log_date = l.log_date
            GROUP BY LDate";
$result =   $this->db->query($query);
return $result->result();

学习点

左连接Group_Concat
Concat
DATE_FORMAT

编辑:
2方法

如果你想用PHP做,这很容易。你可以这样做。第一个模型函数

function fetch_logs($group_id, $limit, $offset)
{
        $select =   array(
                        "DATE_FORMAT(l.log_date,'%a , %b %d , %Y') as LogDate",
                        "GROUP_CONCAT(l.log_id) as LogIDs",
                        "GROUP_CONCAT(l.log_content) as LogContents",
                        "GROUP_CONCAT(l.log_author) as LogAuthors",
                        "GROUP_CONCAT(DATE_FORMAT(l.log_date,'%h:%i %p')) LogTimes"
                    );
        $this->db->select($select);
        $this->db->from('logs AS l');
        $this->db->join('log_group_ref AS r', 'l.log_id = r.log_id');
        $this->db->join('users AS u', 'l.log_author = u.user_id');
        $this->db->where('r.group_id', $group_id);
        $this->db->group_by(l.log_date);
        $this->db->limit($limit, $offset);
        return $this->db->get()->result_array();
}   

And Now in Controller function

function getLogs()
{
    $result =   $this->yourmodel->fetch_logs();
    $data   =   array();
    $i  =   0;
    foreach($result as $row)
    {
        $logids     =   explode(',',$row['LogIDs']);
        $logcontents    =   explode(',',$row['LogContents']);
        $logauthors =   explode(',',$row['LogAuthors']);
        $logtimes       =   explode(',',$row['LogTimes']);
        $counter    =   count($logids);
        $test   =   array();
            for($j=0;$j<$counter;$j++)
            {
                $test[] =   $logcontents[$j] .','. $logauthors[$j] .','.$logtimes[$j];
            }
        $data[$i]['logdata']    =   implode('|',$test);
        $data[$i]['logdate']    =   $row['LogDate'];
        unset($test);
        $i++;
    }
    $viewdata['data']   =   $data;
    $this->load->view('my_view',$viewdata);
}

你可以试试——

$this->db->select("l.log_id, date_format(l.log_date,'%W %M, %d %Y') D, l.log_content, u.username");
        $this->db->from('logs AS l');
        $this->db->join('log_group_ref AS r', 'l.log_id = r.log_id');
        $this->db->join('users AS u', 'l.log_author = u.user_id');
        $this->db->where('r.group_id', $group_id);
        $this->db->order_by('l.log_date','desc');
        $this->db->limit($limit);
        return $this->db->get()->result_array();

我只是格式化了日期(l.log_date)并添加了order_by子句,以便它获取前N天的活动。