我希望有人能帮助我在正确的方向。我目前有一个文件,我将其命名为data.php。在这个文件中,我有以下数据:
$sports_arr = array();
$sports_arr[] = "Basketball";
$sports_arr[] = "Baseball";
$sports_arr[] = "Football";
我在同一个data.php文件中也有以下数组:
$position = array();
$position['Basketball'][] = "Power Forward";
$position['Basketball'][] = "Small Forward";
$position['Basketball'][] = "Center";
$position['Soccer'][] = "Center Forward";
$position['Soccer'][] = "Right Wing";
$position['Soccer'][] = "Left Wing";
$position['Football'][] = "Halfback";
$position['Football'][] = "Fullback";
$position['Football'][] = "Wide Reciever";
$position['Football'][] = "Tight End";
$position['Football'][] = "Center";
问题是我试图找出如何有第一个下拉菜单,目前正在填充以下代码:
<div class="selectStyled">
<select name="Sport1" class="styled">
<option id="default" value="">Your Sport</option>
<?php natsort($sports_arr);
foreach ($sports_arr as $key => $val) {
echo "<option value='" . $val . "' id='position" . $key . "'>" . $val . "</option>";
} ?>
</select>
</div>
这就是我遇到问题的地方。我想要的是基于上面的下拉结果(例如,用户选择棒球),我想要第二个后续下拉填充正确的位置数组。因此,如果他们选择篮球,它会立即动态地填充页面上的第二个下拉框,显示篮球位置。如果他们改变主意并选择Football,它将动态地用足球位置填充第二个下拉框。
这里的任何帮助都是感激的。我遇到了一个大障碍…谢谢你! !
请尝试:
<?php
$sports_arr = array();
$sports_arr[] = "Basketball";
$sports_arr[] = "Baseball";
$sports_arr[] = "Football";
$position = array();
$position['Basketball'][] = "Power Forward";
$position['Basketball'][] = "Small Forward";
$position['Basketball'][] = "Center";
$position['Soccer'][] = "Center Forward";
$position['Soccer'][] = "Right Wing";
$position['Soccer'][] = "Left Wing";
$position['Football'][] = "Halfback";
$position['Football'][] = "Fullback";
$position['Football'][] = "Wide Reciever";
$position['Football'][] = "Tight End";
$position['Football'][] = "Center";
?>
<div class="home">
<select id="s1">
<?php foreach($sports_arr as $sa) { ?>
<option value="<?php echo $sa; ?>"><?php echo $sa; ?></option>
<?php } ?>
</select>
<select id="s2">
</select>
</div>
<script type="text/javascript">
var s1= document.getElementById("s1");
var s2 = document.getElementById("s2");
onchange(); //Change options after page load
s1.onchange = onchange; // change options when s1 is changed
function onchange() {
<?php foreach ($sports_arr as $sa) {?>
if (s1.value == '<?php echo $sa; ?>') {
option_html = "";
<?php if (isset($position[$sa])) { ?> // Make sure position is exist
<?php foreach ($position[$sa] as $value) { ?>
option_html += "<option><?php echo $value; ?></option>";
<?php } ?>
<?php } ?>
s2.innerHTML = option_html;
}
<?php } ?>
}
</script>
大多数情况下,人们使用ajax,但如果你的网络很慢,ajax不是一个好方法。
如果用户在第一个下拉列表中选择了篮球,那么在第二个下拉列表中显示所有的篮球记录。
所以你应该使用AJAX函数onChange()事件的第一个下拉。