如何使用Select2插件在数据库中添加从下拉菜单中选择的多个值

我需要什么:

• 当用户从下拉菜单中选择多个值时，必须在数据库中插入所有值。

我的问题:

• 只插入单个值

  这是我的代码快照:http://postimg.org/image/h3on9ti6r/.

  下面是我使用 的示例代码:

  if(isset($_POST['submit']))
  {
    $team=$_POST['team'];
    $teamname=$_POST['teamname'];
    $query="INSERT INTO teamname(People_Name, Team_Name) VALUES   ('".$team."','".$teamname."')" ;
    $rs=mysql_query($query);
    $num=mysql_num_rows($query);
  }
  

<form id="contactForm" action="" method="post">
<fieldset>                      
    <p>
        <label for="name" >Team</label>
          <input type="hidden" id="123">
       <select multiple id="e2" name="team[]" style="width:300px">
    <?php
    $query= mysql_query("select Distinct Name from users ");
    while($result=mysql_fetch_assoc($query)){
    ?>
       <option value=" <?php echo $result['Name']?> "><?php echo $result['Name']?></option>
       <?php
    }
    ?>
    </select>
    </p>

    <p>
       <label for="Team Name">Enter the Team Name</label>
        <textarea  name="teamname"  id="teamname" type="text" rows="5" cols="20" class="form-poshytip" title="Enter the Team Name"></textarea>
    </p>

    <!-- ENDS send mail configuration -->
    <p><input type="submit" value="Send" name="submit" id="submit" /> <span id="error" class="warning">Message</span></p>
</fieldset>

我已经尝试了我更新的代码，但问题:只有一个文件被插入

   if(isset($_POST['submit']))
 {
$team=$_POST['team'];
  $teamname=$_POST['teamname'];
  $ct = 0; 
  foreach ($team as $value)
     {
  echo $value;
  echo $query="INSERT INTO teamname(People_Name) VALUES ('".$value."')" ;
  $rs=mysql_query($query);
  $num=mysql_num_rows($query);
  serialize($team);
  $ct++;
 }
  $c = 0; 
  foreach ($teamname as $value1)
     {
  echo $value1;
  echo $query1="INSERT INTO teamname(Team_Name) VALUES ('".$value1."')" ;
  $rs1=mysql_query($query1);
  $num=mysql_num_rows($query1);
  serialize($teamname);
  $c++;
 }   
}