我从数据库中获取数据并显示在表中。获取工作正常的所选日期范围之间的日期。
while ($row = mysql_fetch_array($query)) {
$date = $row['tt_date']; //get dates from table column
echo $date; // showing proper values
}
当我添加
echo date('l', strtotime( $date));
或
echo date('l',$date);
一直显示Thursday对于所有从表中检索数据;
应该显示检索日期的正确日期
根据OP的注释，似乎$date变量包含多个日期，因此OP需要爆炸该字符串，并在循环中将.字符更改为-:
$date = '2015.08.31 | 2015.08.31 | 2015.09.02';
echo $date;
//Will output 2015.08.31 | 2015.08.31 | 2015.09.02
//So now here, you need to explode this string with " | "
$datesArray = explode(" | ", $date);
var_dump($datesArray);
//The output is:
//array (size=3)
// 0 => string '2015.08.31' (length=10)
// 1 => string '2015.08.31' (length=10)
// 2 => string '2015.09.02' (length=10)
//Now you need to iterate through on this array
foreach ($datesArray as $dateString) {
//You need to replace the "." character to "-" for the strtotime function
echo date('l', strtotime( str_replace('.','-',$dateString))) ."<br>'n";
}
//Output is:
//Monday
//Monday
//Wednesday
//I've checked the calendar, and it's correct