我试图将不同用户的图片路径上传到数据库。我是相当新的编码器,我读了很多教程,但我仍然挣扎。这是我的控制器,但我甚至不知道如何将图像与用户会话链接。
下面是我的代码:function do_upload()
{
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|jpeg|png';
$config['max_size'] = '100';
$config['max_width'] = '1024';
$config['max_height'] = '768';
$config['overwrite'] = false;
$this->load->library('upload', $config);
if ( ! $this->upload->do_upload())
{
$error = array('error' => $this->upload->display_errors());
$this->load->view('upload_form', $error);
}else
{
$data = $this->upload->data();
$file_array = $this->upload->data('file_name');
$profile['profile_picture'] = $file_array['file_name'];
$this->db->where('username', $this->input->post('username'));
$this->db->update('users', $profile);
$this->load->view('upload_success', $data);
}
}
我的数据库有一个名为users的表,'profile_picture'是路径的字段。当我上传图像时,我只是让所有用户字段都用相同的文件名填充。
感谢大家的提示,我是这样解决的:
function do_upload(){
if($this->session->userdata('is_logged_in'))
{
$id = $this->session->userdata('id');
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|jpeg|png';
$config['max_size'] = '100';
$config['max_width'] = '1024';
$config['max_height'] = '768';
$config['overwrite'] = false;
$this->load->library('upload', $config);
if ( ! $this->upload->do_upload())
{
$error = array('error' => $this->upload->display_errors());
$this->load->view("site_header");
$this->load->view("site_nav");
$this->load->view('upload_form', $error);
}else{
$data = $this->upload->data();
$file_array = $this->upload->data('file_name');
$profile['profile_picture'] = $file_array['file_name'];
$this->db->where('id', $id);
$this->db->update('users', $profile);
$this->load->view('upload_success', $data);
}
}else{
$this->load->view("site_header");
$this->load->view("site_nav");
$this->load->view("login_view");
$this->load->view("site_footer");
}
}
如果您的用途有ID,只需执行imagePath =/upload/avatar/'.$userID.'.jpg'或使用随机文件名并将其存储为新字段