我试图创建一个注册表，但应用程序一直崩溃我想这可能是我的虚拟模拟器的URL，我尝试了10.0.2.2和10.0.3.2，我检查了虚拟框以查看要使用的地址，我得到了192.168.79.2，但它们都不起作用。
这是我的BackgroundTask.java类
public class BackgroundTask extends
AsyncTask<String,Void,String> {
Context ctx;
BackgroundTask(Context ctx){
this.ctx=ctx;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String method= params[0];
String reg_url="http://192.168.79.2/webapp/register.php";
// String login_url="http://10.0.2.2/webapp/login.php";
if(method.equals("register")){
String names=params[1];
String user_name=params[2];
String user_pass=params[3];
try {
URL url= new URL(reg_url);
HttpsURLConnection httpsURLConnection = (HttpsURLConnection)
url.openConnection();
httpsURLConnection.setRequestMethod("POST");
httpsURLConnection.setDoOutput(true);
OutputStream OS=httpsURLConnection.getOutputStream();
BufferedWriter bufferedWriter =new BufferedWriter(new
OutputStreamWriter(OS, "UTF-8"));
String data = URLEncoder.encode("user", "UTF-8")+"="+URLEncoder.encode(names, "UTF-8")+"&"+
URLEncoder.encode("user_name", "UTF-8")+"="+URLEncoder.encode(user_name, "UTF-8")+"&"+
URLEncoder.encode("user_pass", "UTF-8")+"="+URLEncoder.encode(user_pass, "UTF-8");
bufferedWriter.write(data);
bufferedWriter.flush();
OS.close();
InputStream IS = httpsURLConnection.getInputStream();
IS.close();
return "Registration success";
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
;
}
return null;
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
@Override
protected void onPostExecute(String result) {
Toast.makeText(ctx,"result" ,Toast.LENGTH_LONG).show();
}
}
这是我的Register.java活动
public class Register extends Activity {
EditText ET_NAME, ET_USER_NAME, ET_USER_PASS;
String name, user_name, user_pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
ET_NAME=(EditText) findViewById(R.id.name);
ET_USER_NAME=(EditText) findViewById(R.id.username);
ET_USER_PASS=(EditText) findViewById(R.id.pass);
}
public void userReg(View view){
name= ET_NAME.getText().toString();
user_name=ET_USER_NAME.getText().toString();
user_pass=ET_USER_PASS.getText().toString();
String method= "register";
BackgroundTask backgroundTask = new BackgroundTask(this);
backgroundTask.execute(method, name, user_name, user_pass);
finish();
}
}
这是我的register.php文件
<?php
require"init.php";
$names=$_POST["names"];
$user_name=$_POST["user_name"];
$user_pass=$_POST["user_pass"];
$sql_query="insert into info values('$names', '$user_name', '$user_pass');";
if(mysqli_query($con, $sql_query)){
//echo"<h3>Data insertion Success...</h3>";
}
else{
//echo"Data insertion error...".mysqli_error($con);
}
?>您的解决方案
据我所见，第一行应该是URLEncoder.encode("user", "UTF-8")吗？很明显，PHP表单显示$names=$_POST["names"];，这意味着POST变量应该为names。
如果您的数据库没有为null变量配置，它将出错。
String data = URLEncoder.encode("user", "UTF-8")+"="+URLEncoder.encode(names, "UTF-8")+"&"+
URLEncoder.encode("user_name", "UTF-8")+"="+URLEncoder.encode(user_name, "UTF-8")+"&"+
URLEncoder.encode("user_pass", "UTF-8")+"="+URLEncoder.encode(user_pass, "UTF-8");
将异步任务调用为
ArrayList<String> params = new ArrayList<String>();
params.add(name);
params.add(userId);
params.add(passw);
new registerTask().execute(params);
试试这个：
public class registerTask extends AsyncTask<ArrayList<String>, Void, ArrayList<String>> {
@Override
protected void onPreExecute() {
progress1.setVisibility(View.VISIBLE);
}
protected ArrayList<String> doInBackground(ArrayList<String>... passing) {
ArrayList<String> result = new ArrayList<String>();
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.79.2/webapp/register.php");
String responses = null;
ArrayList<String> data = passing[0];
String name = data.get(0);
String uid = data.get(1);
String passw = data.get(2);
int ik;
try {
//add data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("names", name));
nameValuePairs.add(new BasicNameValuePair("user_name", uid));
nameValuePairs.add(new BasicNameValuePair("user_pass", passw));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
//execute http post
HttpResponse response = httpclient.execute(httppost);
//You will get the response from server in response
HttpEntity entity = response.getEntity();
String content = EntityUtils.toString(entity);
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
return "Success"; //return result
}
protected void onPostExecute(ArrayList<String> result) {
}
}
我不知道我是否错过了什么。。。。试试这个。。
谢谢@lefsFrare我的导入有问题
i更改自：javax.net.ssl.HttpsURLConnection;至：java.net.HttpURLConnection;