有没有一种算法可以找到它们之间没有共同密钥的数组? - is there any algorithm which can find arrays which do not have common key between them

is there any algorithm which can find arrays which do not have common key between them

$array1 = array (
    '1' => A,
    '2' => B,
    '3' => C
);
$array2 = array (
    '1' => A,
    '4' => B,
    '5' => D
);
$array3 = array (
    '5' => A,
    '6' => E,
    '7' => D
);
$array4 = array (
    '4' => A,
    '7' => B,
    '10' => C
);

我想找出所有不同键的数组，数组之间不应该有一个共同的键。

$array1 - $array3, $array1 - $array4是两个没有公共键的组合。算法的输出应该是这些组合

如果两个数组没有相同的键，则

count(array_intersect_key($a, $b))应为0

要从两个数组中查找唯一键，可以使用

$newArray = array_diff_key($targetArray, $compArray);

类似于

function test() {
    $arrays = func_get_args();
    for($i = 0; $i < count($arrays); $i++) {
        if (($i + 1) == count($arrays))
        break;
        for($k = $i; $k < count($arrays); $k++) {
            if (count(array_intersect_key($arrays[$i], $arrays[$k])) == 0){
                var_dump($arrays[$i]);
                var_dump($arrays[$k]);
                printf('<hr />');
            }
        }   
    }
}
print_r(test($array1, $array2, $array3, $array4));

应该能解决你的问题