我需要从PHP上传一个SCORM包到D2L实例。我有所有需要的键和数据，因为其他查询(例如GET请求获取用户配置文件数据)。我还测试了从Chrome的高级REST插件上传，它工作正常，给仓库。lrwpublishresult与新的学习对象id等
当我试图从PHP使用CURL(我的代码是基于GettingStartedSample)上传时，我总是得到"对象移动到/d2l/error/404"响应。我读到这可能是由URL的"https"前缀引起的，我应该使用CURLOPT_FOLLOWLOCATION选项，但它没有帮助。它遵循重定向并返回空响应。
我做一个PUT请求到
/网站/api/lr/1.0/对象/?repositoryId = REPO_ID
有人有这个工作代码，可以给我一些提示吗?谢谢!
下面是一些PHP代码:
$apiRoute = "/d2l/api/lr/1.0/objects/?repositoryId=" . $repoID;
$id = uniqid();
$data = "--" . $id . "'r'n".
"Content-Disposition: form-data; name='"Resource'"; filename='"HW_SCORM.zip'"'r'n".
"Content-Type: application/zip'r'n".
"'r'n".
file_get_contents("HW_SCORM.zip") . "'r'n".
"--" . $id . "--";
$uri = $opContext->createAuthenticatedUri($apiRoute, "PUT");
curl_setopt($ch, CURLOPT_URL, $uri);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'PUT');
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
"Content-Type: multipart/form-data; boundary=" . $id,
"Content-Length: " . strlen($data))
);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
$response = curl_exec($ch);
它将发送如下内容:
Content-Type: multipart/form-data; boundary=ba5567548ef846b595f2d8f0ee5a1ca4
Accept: */*
Content-Length: {size}
--ba5567548ef846b595f2d8f0ee5a1ca4
Content-Disposition: form-data; name="Resource"; filename="HW_SCORM.zip"
Content-Type: application/zip
{file_data}
--ba5567548ef846b595f2d8f0ee5a1ca4--
作为回应，你应该看到类似
HTTP/1.1 100 Continue
HTTP/1.1 200 OK
Cache-Control: no-cache, no-store
Pragma: no-cache
Content-Length: 73
Content-Type: application/json; charset=UTF-8
Expires: -1
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET
Date: Wed, 17 Apr 2013 21:02:42 GMT
{"IdentId":15805,"Version":1,"ExecutionMessage":null,"ExecutionStatus":0}
随机猜测:如果您在文件内容之后和结束边界标记之前忘记了尾随换行，那么看起来LOR将发送303响应，告诉您转到404页面。