我想使用for循环从数组中匹配最后一个$data[$ I]和下一个$data[$ I]。我怎么能那样做呢?
下面是代码…
while($row=mysql_fetch_array($resultQuery))
{
echo "<br> Hotel Code : " .$row['HotelCode'];
$info=(str_replace('YES ','',htmlspecialchars_decode($row['PAmenities'])));
$str_replace='NO ';
//$info=(str_replace('NO ','',htmlspecialchars_decode($row['PAmenities'])));
$info_new=array();
$info_new =(array_unique(explode(";",$info)));
echo "<br> Hotel Features : " ;
$string =implode(",",$info_new);
$string = (str_replace('&apos,',"'",htmlspecialchars_decode($string)));
//echo $string;
$data=array();
$data=(explode(",",$string));
for($i = 0; $i < count($data); $i++)
{
echo (str_replace('NO ','',$data[$i])).",";
}
echo "<hr>";
Double bed,Bathroom,Shower,Bathtub,Hairdryer,Terrace,Balcony,Safe,Central heating,Individually adjustable heating,TV,Individually adjustable air conditioning,Direct dial telephone,Small pets allowed under 5 kg,Small pets allowed under 5 kg,Large pets allowed over 5 kg,Large pets allowed over 5 kg,**Wheelchair-accessible,Wheelchair-accessible,**Car park,Car park,Garage,24-hour reception,Wi-fi,Laundry service,Launderette,Lift access,Bar,Restaurant,Highchairs,TV lounge,Year of construction - 1970,Year of most recent renovation - 2005,Number of floors main building - 5,Total number of rooms - 37,Single rooms - 4,Double rooms - 27,Suites - 2,Connecting rooms,Connecting rooms,Hotel,Breakfast buffet,A la carte lunch,Set menu dinner,Nearest Bus / Metro Stop - 5000 m,
尝试:
for($i = 0; $i < count($data); $i++)
{
if($data[$i] == $lastdata)
{
// do stuff.
}
echo (str_replace('NO ','',$data[$i]));
$lastdata = $data[$i]
}
如果你不想在循环中比较前一个值，总是将它存储在循环结束时的一个变量中。