我不能创建一个合适的查询,它可以选择与一个特定图像连接的所有评论,并获得这些评论的作者。我想创建一个这样的查询:
select a comment where comment_id == image_id && user_id(table comments) == user_id(table users)
MySQL部分:
Table 'comments'
id | comment | user_id | image_id |
1 | test 1 | 1 | 1 |
2 | test 2 | 1 | 2 |
3 | test 3 | 2 | 1 |
Table 'users'
id | name |
1 | test1 |
2 | test2 |
Table 'images'
id | img |
1 | test.jpg |
2 | test.jpg |
3 | test.jpg |
4 | test.jpg |
控制器部分:$imageId = $filter->filter ($request->getParam('id'));
$this->view->imageId = $filter->filter ($request->getParam('id'));
$this->view->imageChosen = $images->fetchRow($images->select()->where('id = ?', $imageId));
$users = new Users();
$userChosen = new Users();
$comments = new Comments();
$this->view->comments = $comments->fetchAll();
$this->view->userChosen = $users->fetchRow($users->select()->where('id = ?', $this->view->imageChosen->author_id));
$this->view->commentsChosen = $comments->fetchAll($comments->select()->where('id = ?', $imageId));
视图部分:
for ($i=0; $i < count($this->commentsChosen); $i++) {
echo $this->commentChosen[$i]->comment;
}
现在我只看到第一条评论。我的意思是我需要属于每个图片以及作者信息的所有评论。谢谢你的帮助!
正如您所说,您可以通过查询获取图像信息,我将扩展它以获取用户信息:
$select = $comments->select()->setIntegrityCheck(false)
->from('comments')
->joinInner('users', 'users.id = comments.user_id')
->where('comments.image_id = ?', $this->view->imageChosen->id);
$this->view->commentsChosen = $comments->fetchAll($select);
生成的查询将是:
SELECT comments.* users.* FROM comments
INNER JOIN users ON users.id = comments.user_id
WHERE comments.image_id = [Your_id_here]
我希望这对你有帮助!
我已经设法得到了属于每张图片的所有评论。
控制器:
$this->view->commentsChosen = $comments->fetchAll($comments->select()->where('image_id = ?', $this->view->imageChosen->id));
视图:
for ($i=0; $i<count($this->commentsChosen); $i++) {
echo $this->commentsChosen[$i]->comment;
//Have 'user_id' only
echo $this->commentsChosen[$i]->user_id;
}
但是,我仍然无法获得作者的详细信息。