//this is the php code that i call in another file
if ( isset($_POST['star'])){
$check_vote = $_POST['star'];
$new_rate = 0;
***$video1_id = $_POST["$video_id"];*** //the problem is here
$find_video = mysqli($con, "SELECT * FROM videos WHERE video_id='$video_id1'");
// and this is the html code that another php function echoes//
form name='$video_id' method='POST'
input class='star star-5' id='star-5' type='radio' name='star' value='5'/>
<label class='star star-5' for='star-5'></label>
<input class='star star-4' id='star-4' type='radio' name='star' value='4'/>
<label class='star star-4' for='star-4'></label>
<input class='star star-3' id='star-3' type='radio' name='star' value='3'/>
<label class='star star-3' for='star-3'></label>
<input class='star star-2' id='star-2' type='radio' name='star' value='2'/>
<label class='star star-2' for='star-2'></label>
<input class='star star-1' id='star-1' type='radio' name='star' value='1'/>
<label class='star star-1' for='star-1'></label>
<input type='submit' name='$video_id' value='Vote' id='$video_id'>
</form>
// my problem is that i want to take the variable $video_id(either form the form either from the submit-button) to search for the specific video but i cant. i tried $video1_id = $_POST["$video_id"]; and $video1_id = $_POST['$video_id']; and this $video1_id = $_POST[$video_id]; and this $video1_id = $_POST['.$video_id'];
感谢您的宝贵时间
你不能像$_POST["$video_id"]那样获得变量的值，从一个带有文本或隐藏字段的字段发送它，然后从另一边获得它。
你必须把你的php代码从html中分离出来。"$blabla"语法错误。在PHP中添加PHP开始和结束标签，比如
所以你可以在html 中使用你的PHP代码例如<h1><?=$video_id?> </h1>
<input type="hidden" name="vID" value="<?=$video_id?>" />
，然后写成
$myVideoId = $_POST["vID"];
//解决方案在PHP echo HTML代码是这样的…
form name='$video_id' method='POST'
input class='star star-5' id='star-5' type='radio' name='star' value='5'/>
label class='star star-5' for='star-5'></label>
input class='star star-4' id='star-4' type='radio' name='star' value='4'/>
label class='star star-4' for='star-4'></label>
input class='star star-3' id='star-3' type='radio' name='star' value='3'/>
label class='star star-3' for='star-3'></label>
input class='star star-2' id='star-2' type='radio' name='star' value='2'/>
label class='star star-2' for='star-2'></label>
input class='star star-1' id='star-1' type='radio' name='star' value='1'/>
label class='star star-1' for='star-1'></label>
input type='submit' name='$video_id' value='Vote' id='$video_id'>
/form
//在另一个函数中正确的PHP代码是这个
if (isset($_POST['star']) &&收取($ _POST [' video_id '])) {$check_vote = $_POST['star'];
$new_rate = 0;
$video_id = $_POST['video_id'];
$sql = " SELECT * FROM videos WHERE video_id = '$video_id' ";
$find_video = mysqli_query($con, $sql);