我需要插入查询结果作为另一个查询的输入这是我尝试过的代码,请立即帮助我我需要从query1中获取id并将其作为$id
插入到query2中class Get_db extends CI_Model{
public function get_All(){
$query1 = $this->db->query("SELECT name,id from companydetails");
return $query->result();
}
public function getBranches(){
$query2 = $this->db->query("SELECT branches.name FROM branches WHERE branches.companyid=$id ");
return $query2->result();
}
}
我需要从query1中获取id并将其插入query2中作为$id
get_All()方法返回一个对象,因此您可以使用:
$resultQuery1 = get_All();
$output = array();
foreach($resultQuery1 as $q)
$output[$q->id] = getBranches($q->id);
在getBranches方法中你应该接受一个参数
public function getBranches($id) {...}
$output变量是一个数组,包含getBranches方法的所有结果。
试试下面的代码:
<?php
$this->db->select('name,id')
->from('companydetails');
$qry = $this->db->get();
$res = $qry->result();
foreach($res as $val){
$this->db->select('name')
->from('branches')
->where('companyid', $val->id);
$qry2 = $this->db->get();
$res2 = $qry->result();
}
return $res2;
?>
$res数组是第一个查询的执行结果,它将作为第二个查询
这就行了
public function get_All()
{
$this->db->select('name, id');
$query = $this->db->get('companydetails');
if ($query->num_rows () > 0)
{
$result = $query->result();
foreach($result as $company)
{
$company->branches = $this->getBranches($company->id);
}
return $result;
}
else
{
return false;
}
}
public function getBranches($id)
{
$query = $this->db->get_where('branches', array('id' => $id));
return $query->result();
}
可以在中使用一个简单的函数。使用 JOIN
-
<?php
class Get_db extends CI_Model
{
public function get_company_branches()
{
$this->db->select('companydetails.name','companydetails.id','branches.name');
$this->db->from('companydetails');
$this->db->join('branches', 'companydetails.id = branches.companyid');
$query = $this->db->get();
$result = array();
if($query->num_rows() > 0)
$result = $query->result_array();
echo '<pre>'; print_r($result); // Your expected result
}
}
或如果您不想使用JOIN并直接回答您的问题,那么您可以使用
模型:
...
...
public function get_All()
{
$this->db->select("id","name");
$this->db->from("companydetails");
$query = $this->db->get();
return $query->result();
}
public function getBranches($id)
{
$this->db->select("name");
$this->db->from("branches");
$this->db->where("companyid", $id)
$query = $this->db->get();
return $query->result();
}
控制器:
...
...
public function somename()
{
$companies = $this->get_db->get_All();
$branches = array();
foreach($companies as $company)
{
$branches[] = $this->get_db->getBranches($company->id);
}
echo '<pre>'; print_r($branches); // Expected result
}
controller
public function home(){
$this->load->model('get_company_model');
$this->load->view('view_header');
$data['results'] = $this->get_company_model->get_all();
$this->load->view('view_nav',$data);
$this->load->view('view_content');
$this->load->view('view_footer');
}
模型 public function get_All(){
$query = $this->db->query("SELECT name,id from companydetails");
return $query->result();
}
public function get_branch($companyID){
$query = $this->db->query("SELECT name,id from branches WHERE companyid='".$companyID."'");
return $query->result();
}
视图<div>
<ol class="tree">
<li>
<label for="folder1"><?=$row->name?></label> <input type="checkbox" id="folder1" />
<ol>
<?php
$myresult=$this->get_company_model->get_branch($row->id);
foreach($myresult as $row2):
?>
<li class="file"><a href="#"><?=$row2->name?></a></li>
<?php
endforeach;
?>
</ol>
</div>
<?php
endforeach;
?>