我有一个MySQL数据库,那里有我想加载到Listview的图像blobs。
我正试图利用毕加索。但问题是我如何做一个POST请求,发送参数($_POST在PHP中)-将其转换为url,最后库加载到一个imageview?哪个是最好的选择?
我当前获取图像的实现如下:
public View getView(final int position, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
----------------------------
----------------------------
if (!"N".equalsIgnoreCase(listOfPosts.get(position).getHasImage()) ) {
if(mMemoryCache.get(postId)== null )
new GetPrimaryImages(position, holder).execute(image);
else
holder.ivPrimaryImage.setImageBitmap(mMemoryCache.get(postId));
}else {
holder.ivPrimaryImage.setImageResource(R.drawable.search);
}
return rowView;
}
GetPrimaryImages类如下所示:
public class GetPrimaryImages extends AsyncTask<Image, Void, Bitmap> {
int mPosition;
Holder mHolder;
public GetPrimaryImages(int position, Holder holder){
mPosition = position;
mHolder = holder;
}
ImageView imageView = null;
protected Bitmap doInBackground(Image... images) {
this.imageView=images[0].getImg();
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("postid",(String)(this.imageView.getTag()) ));
JSONObject json;
if(mHolder.position == mPosition)
json = jsonParser.makeHttpRequest(CommonResources.getURL("get_primary_image"),
"POST", params);
else {
json = null;
cancel(true);
}
if(json == null){
//latch.countDown();
return null;
}
Log.d("Fetching Image",imageView.getTag()+ json.toString());
// check for success tag
String TAG_SUCCESS = "success";
try {
int success = json.getInt(TAG_SUCCESS);
if (success == 0) {
image = json.getString("primaryimage");
}
} catch (JSONException e) {
e.printStackTrace();
}
return getImage(image);
}
protected void onPostExecute(Bitmap result) {
if (mHolder.position == mPosition) {
mMemoryCache.put((String) imageView.getTag(), result);
imageView.setImageBitmap(result);
}
}
}
Tty this
Picasso.with(上下文).load (url) .placeholder (R.drawable.no_image) .into (imageview);