我在php有一个错误,我不知道如何解决这个问题。顺便说一下,这是我学校课上的例子,所以我真的不知道那里发生了什么。这被支持为主/细节导航。
<?php
$mysqli = new mysqli("localhost", "root", "", "base");
$stmt = $mysqli->prepare('SELECT * FROM aeromiting WHERE id = ":id"');
echo $mysqli->error;
$stmt->bind_param(':id', $_GET['id']);
var_dump($stmt);
$data = $stmt->execute();
?>
警告:mysqli_stmt::bind_param(): type中元素的数量定义字符串不匹配绑定变量的数量C:'xampp'htdocs'test1'detail.php第20行对象(mysqli_stmt)#2 (10){["affected_rows"]=> int(0)("insert_id")=> int(0)("num_rows")=>int(0)("param_count")=> int(0)("field_count")=> int(4)("errno")=>Int (0) ["error"]=> string(0)" ["error_list"]=> array(0) {}[" sqlstate "] =>字符串(5)"00000" ["id"]=> int(1)}
如果你想在PDO中做,试试这个…
<?php
$host = 'localhost'; $db = 'base'; $user = 'root'; $pw = '';
$conn = new PDO('mysql:host='.$host.';dbname='.$db.';charset=utf8', $user, $pw);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
try {
$id = $_GET['id'];
$sql = "SELECT * FROM aeromiting WHERE id=:id";
$query = $conn->prepare($sql);
$query->bindValue(':id', $id, PDO::PARAM_INT);
$query->execute();
$row = $query->fetch(PDO::FETCH_ASSOC);
$totalRows = $query->rowCount();
} catch (PDOException $e) {
die("Could not get the data: " . $e->getMessage());
}
?>
您在这里混合了api。mysql不能接受字符串或类似的参数
$stmt = $mysqli->prepare('SELECT * FROM aeromiting WHERE id = ":id"');
$stmt->bind_param(':id', $_GET['id']);
应该$stmt = $mysqli->prepare('SELECT * FROM aeromiting WHERE id = ?');
$stmt->bind_param('i', $_GET['id']);
这当然是假设$_GET['id']
是一个整数(因此bind_param
中的'i'
。如果是字符串,将i
替换为s
。
你应该得到一个bind_result
以及,所以你实际上绑定结果从数据库到一些变量。查看MySQLi文档