我对这些代码有问题：
密码.php:
<html>
<head>
<title>Password!</title>
<meta charset="UTF-8">
</head>
<body>
<ul>
<form action="check.php" method="POST">
<li><input type="password" name="no1" placeholder="enter your password"></li>
<li><input type="submit" value="GO!"></li>
</form>
</ul>
</body>
这里是password2.php:
<html>
<head>
<title>Password!</title>
<meta charset="UTF-8">
</head>
<body>
<ul>
<form action="check.php" method="POST">
<li><input type="password" name="name" placeholder="verify your password"></li>
<li><input type="submit" value="GO!"></li>
</form>
</ul>
</body>
这是check.php：
<?php
$enter = $_POST['no1'];
if (empty($enter)) {
echo "Please enter password!";
}
if (!(empty($enter))) {
echo "Your password is $enter";
}
?>
<html>
<body>
<p><a href="password2.php">Move on!</a></p>
</body>
</html>
<?php
$check = $_POST['name'];
if ($check == $enter) {
echo "Acces Granted";
}
if (!($check == $enter)) {
echo "Acces denied!";
}
?>
我遇到的麻烦是：
- check.php无法识别password2.php中的"name">
- 我无法验证密码
因为$_POST变量在请求之间不持久，所以它不起作用。您可以将第一个表单中的值存储在$_SESSION变量中，并从会话中检索它。
有关php会话的更多信息，请点击
除了check.php之外，保持问题中的所有内容不变，这是修改后的：
<?php
//starting the session in PHP
session_start();
$enter = null;
// this is all the logic you need for retrieving `no1` from POST or SESSION
if (isset($_POST['no1'])){
$enter = $_POST['no1'];
$_SESSION['no1'] = $enter;
}elseif(isset($_SESSION['no1'])){
$enter = $_SESSION['no1'];
}
if (empty($enter)) {
echo "Please enter password!";
}
if (!(empty($enter))) {
echo "Your password is $enter";
}
?>
<html>
<body>
<p><a href="password2.php">Move on!</a></p>
</body>
</html>
<?php
$check = $_POST['name'];
if ($check == $enter) {
echo "Acces Granted";
// you can comment the next line if you are debugging,
// but after that you should destroy de session so you don't have a password as plain text
session_destroy();
}
if (!($check == $enter)) {
echo "Acces denied!";
}
?>