未捕获异常'；PHPExcel_Reader_Exception'；无法打开带有消息的以供阅读

我正在为用户创建一个表单，允许他们上传.csv文件和xls/xlsx文件。目前，该程序确实允许他们上传.csv文件，这些文件用于更新我正在处理的Oracle 11g数据库。然而，我似乎不知道如何打开，然后将xsl/xlsx文件右键单击csv的。我一直收到这个错误：

Fatal error: Uncaught exception 'PHPExcel_Reader_Exception' with message 'Could not open uploaded.xls for reading! File does not exist, or it is not readable.' in /opt/apache/servers/planninganddesign/htdocs/LG/SLCCA/Classes/PHPExcel/Shared/OLERead.php:80 Stack trace: #0 /opt/apache/servers/planninganddesign/htdocs/LG/SLCCA/Classes/PHPExcel/Reader/Excel5.php(1164): PHPExcel_Shared_OLERead->read('uploaded.xls') #1 <DIRECTORY> (612): PHPExcel_Reader_Excel5->_loadOLE('uploaded.xls') #2 /opt/apache/servers/planninganddesign/htdocs/LG/SLCCA/update_handler2.php(12): PHPExcel_Reader_Excel5->load('uploaded.xls') #3 {main} thrown in /opt/apache/servers/planninganddesign/htdocs/LG/SLCCA/Classes/PHPExcel/Shared/OLERead.php on line 80 

这是一个很长的错误，但我认为第一行是我目前的主要问题。

update2.php(表单([我怀疑你是否需要这个]：

<?php require('reader.php'); ?>
<form name="file" enctype="multipart/form-data" action="update_handler2.php" method="post" >
   <u>GF:</u> <input type="file" name="uploaded"><br>
   <u>GF:</u> <input type="number" name="numbers"><br>
   <input type="submit" value="Submit">
</form>

update_handler2.php(处理程序(：

<?php require_once'Classes/PHPExcel/IOFactory.php'; ?>
<?php
    $file = $_FILES['uploaded']['tmp_name'];
    $inputFileType = 'Excel5';
    $inputFileName = '$file';
    $objReader = PHPExcel_IOFactory::createReader($inputFileType);
    $objPHPExcelReader = $objReader->load($inputFileName);
    $loadedSheetNames = $objPHPExcelReader->getSheetNames();
    $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcelReader, 'CSV');
    foreach($loadedSheetNames as $sheetIndex => $loadedSheetName) {
        $objWriter->setSheetIndex($sheetIndex);
        $objWriter->save($loadedSheetName.'.csv');
    }
?>

有人知道如何解决这个问题吗？