如何在PHP中从下拉列表中获得选定的值 - How to get the selected value from dropdown list in PHP?

How to get the selected value from dropdown list in PHP?

本文关键字：下拉列表 PHP | 更新日期: 2023-09-27

我无法检索选定的下拉列表值到PHP变量

<!DOCTYPE html>
<html>
<body>
<form action="#" method="post">
<select name="Color">
<option value="Red">Red</option>
<option value="Green">Green</option>
<option value="Blue">Blue</option>
<option value="Pink">Pink</option>
<option value="Yellow">Yellow</option>
</select>    
</form>
<?php
$selected_val = $_POST['Color'];  // Storing Selected Value In Variable
echo "You have selected :" .$selected_val;  // Displaying Selected Value 
?>
</body>
</html>

请帮。

我认为你应该使用javascript，我给你一个简单的脚本，将为你选择的选项值。

看一看:

function run() {
    document.getElementById("resultColorValue").innerHTML = document.getElementById("Color").value;
}

<p>Choose your Color:</p>
<select id="Color" onchange="run()">  <!--Call run() function-->
     <option value=""></option>
     <option value="red">Red</option>
     <option value="green">Green</option>
     <option value="blue">Blue</option>
     <option value="yellow">Yellow</option>     
</select>
<p>Your color is: </p><p id="resultColorValue"></p>

请让我知道，如果这是你正在寻找的:)

我建议使用多个

<form action="#" method="post">
  <select name="Color[]">
    <option value="Red">Red</option>
    <option value="Green">Green</option>
    <option value="Blue">Blue</option>
    <option value="Pink">Pink</option>
   <option value="Yellow">Yellow</option>
  </select>
  <input type="submit" name="submit" value="Submit" />
</form>

php:

<?php
  if(isset($_POST['submit'])) {
     foreach ($_POST['Color'] as $select)
     {
       echo $select;
     }
   }
?>