以下是我必须复制的内容:
curl --basic
--user testuser:testuser
--form xml=@newdoc.xml
--form data1=@mynewfile.xml
http://localhost:9263/repository/document
到目前为止我写的是:
$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_USERPWD, "user:pass");
curl_setopt($curl_handle,CURLOPT_URL, "http://localhost:9263/repository/document");
curl_setopt($curl_handle,CURLOPT_RETURNTRANSFER,1);
curl_setopt($curl_handle,CURLOPT_POST, 1);
$post = array("xml"=>"@e:/path_to_file/old.xml","data1"=>"@e:/path_to_file/new.xml");
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, $post);
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);
不考虑API没有返回错误的事实,对API的调用似乎没有做任何事情,我的CURL翻译好吗?我只是想从等式中去掉一些东西。
Edit #1:在清理我的帖子(并删除调试输出)时,我删除了$buffer = curl.exec($curl_handle)行…
编辑#2:根据Fanis的建议,我替换了文件调用
$old_xml_string = daisy_exec_query("http://localhost:9263/repository/document/8-Multimedia?branch=1&language=2");
//omited dom operations
$new_xml_string = $dom->saveXML();
$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_USERPWD, "user:pass");
curl_setopt($curl_handle,CURLOPT_URL, "http://localhost:9263/repository/document");
curl_setopt($curl_handle,CURLOPT_RETURNTRANSFER,1);
curl_setopt($curl_handle,CURLOPT_POST, 1);
$post = array("xml"=>$old_xml_string,"data1"=>$new_xml_string);
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, $post);
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);
(根据TekiusFanatikus的建议发表评论作为答案)
curl中的"@"操作符不能像PHP的curl函数那样包含文件的内容。您需要将文件的内容作为字符串转换为变量,并将其传递给CURLOPT_POSTFIELDS。