我有以下表格:
tbl_users
===============
uid
username
password
gid
tbl_groups
===============
gid
name
type
我试图找出如何使用sqlmapper在f3能够查询两个表，其中用户名等于$_POST["username"]，并能够获得组的名称和类型以及。是否有可能使用此框架与sqlmapper连接查询?
我已经到处找了，找不到任何关于这个的例子。
你可以尝试设置一些虚拟字段:
$mapper->group_name = 'select name from tbl_groups where tbl_groups.gid=tbl_users.gid';
$mapper->group_type = 'select type from tbl_groups where tbl_groups.gid=tbl_users.gid';
$mapper->load(array('uid = ?',123));
echo $mapper->group_name;
下面是{VIEW}:
的示例我已经实现了这里的分页SQL Mapper使用视图view_user_list_with_referral
$dropInstantWinnerView = $this->db->exec("DROP VIEW IF EXISTS view_user_list_with_referral;");
$createInstantWinnerView = $this->db->exec("CREATE VIEW view_user_list_with_referral AS SELECT u.fb_id, fb_link, name, r.referred_by, u.created FROM users u LEFT OUTER JOIN referral r ON u.fb_id=r.joinee ");
$user = new 'DB'SQL'Mapper($this->db,'view_user_list_with_referral');
$limit = 20;
$page = Pagination::findCurrentPage();
$order_condition = F3::get("PARAMS.order_condition");
$order_class= "";
if(!empty($order_condition)){
$cond = explode(":", $order_condition);
$option = array('order' => $cond[0].' '.$cond[1]);
if($cond[1]=='ASC'){
$order_condition = $cond[0].':DESC';
$order_class = ":DESC";
}else{
$order_condition = $cond[0].':ASC';
$order_class = ":ASC";
}
}else{
$option = array('order' => 'created DESC');
}
$subset = $user->paginate($page-1, $limit, null, $option);
$pages = new Pagination($subset['total'], $limit);
$pages->setTemplate("admin/pagebrowser.html");
F3::set('pagebrowser', $pages->serve());
//echo "<pre>";print_r($subset);exit;
F3::set('page', $page);
F3::set('order_condition', $order_condition);
F3::set('total_found_records', $user->count());
我希望它能节省一些人的时间:)