文件夹路径为f1/f2/。f1和f2都是文件夹F2文件夹包含许多子文件夹,如ff0,ff1,ff2,ff3。F2还包含一个名为copy_folder的文件夹。(路径为f1/f2/copy_folder)。我需要剪切和复制ff0,ff1,ff2,ff3中的所有内容以及文件夹(ff0,ff1,ff2,ff3)到路径是f1/f2/copy_folder . I。E,经过所有的处理后,copy_folder应该分别包含ff0,ff1,ff2,ff3及其内容。同样应该从旧文件夹中删除。E从文件夹f2
实际上我在php 5.3中用函数做了这个"复制"。这是我的示例代码mkdir(f1.f2/copy_folder/ff0)//我在copy_folder里面创建了一个文件夹Copy (f1/f2/ff0/t1.exe,copy_folder/ff0)//将内容拷贝到copy_folder中的ff0取消链接(f1/f2/ff0)//删除旧文件夹ff0
我在php 5.3中这样做了。但是它在php 5.2.1中不起作用。有什么问题吗?我使用zend框架工作。我在数组中使用一些细节('$arrNewClosedIncidentsDetails')
foreach($arrNewClosedIncidentsDetails as $arrNewClosedDet)
{ //iteration of closed incident details there by taking the old path
$strOldPath = $config->paths->releaseattach.'/'.$arrNewClosedDet['strPatchPath']; //taking the
旧路如果(is_dir (strOldPath美元))
{//如果文件是目录
$strNewFolderPath = $config->paths->closedreleaseattach.'/'.$arrNewClosedDet['strFolderName'];
//taking the new folder path to which old folder and sub files have to copied
mkdir($strNewFolderPath);
//making the directory in new path (with old folder name)
chmod($strNewFolderPath, 0777);
//giving permission to this created folder
$arrNewFolderRelatedFiles = scandir($strOldPath);
//scan all files from old folder
foreach($arrNewFolderRelatedFiles as
$objNewFolderRelatedFiles){//遍历旧文件夹中的所有文件
if($objNewFolderRelatedFiles != '.' && $objNewFolderRelatedFiles != '..')
{
//remove default dot elements,which will present as the first and second array value
if (copy($strOldPath.'/'.$objNewFolderRelatedFiles, $strNewFolderPath.'/'.$objNewFolderRelatedFiles)) {
//将所有跟踪到的文件复制到新路径下创建的相应文件夹中chmod ($ strNewFolderPath。"/"。objNewFolderRelatedFiles 0777美元);//对新文件夹
中创建的所有文件赋予权限 unlink($strOldPath.'/'.$objNewFolderRelatedFiles); //delete the files from old folder
}
}
}
rmdir($strOldPath); //remove all old folders
}
}
Thanks in advance
可以使用rename
函数。rename(old_dir_name, new_dir_name)
。http://php.net/manual/en/function.rename.php