我有麻烦让这些数组正确嵌套。我正在从SQL数据库中抓取所有行,并为我的crud应用程序构建一个数组以JSON输出。一个类别很容易,但客户端现在想要子类别,这就是我遇到的主要问题。我试图将这些子类别嵌套到类别中。两者我都能做到,但我没能让它们一起工作。以下是我的PHP代码:
while ($row = $query->fetch_assoc()) {
$categories[$row['category']][] = array(
$row['subcategory'] => $subcategories[$row['subcategory']][] = array(
'id' => $row['id'],
'item_name' => $row['item_name'],
'description' => $row['description'],
'price' => $row['price'],
),
);
}
foreach ($categories as $key => $value) {
$category_data[] = array(
'category' => $key,
'category_list' => $value,
);
}
foreach ($subcategories as $key => $value) {
$subcategory_data[] = array(
'subcategory' => $key,
'subcategory_list' => $value,
);
}
当我json_encode($category_data)我得到以下JSON:
[
{
"category": "Beer",
"category_list": [
{
"Draft Beer": {
"id": "1",
"item_name": "Yuengling",
"description": "Lager. Pottstown, Pa. An American classic."
}
},
{
"Draft Beer": {
"id": "6",
"item_name": "Bud Light",
"description": "American Light Lager"
}
},
{
"Domestic Bottles": {
"id": "9",
"item_name": "Stone IPA",
"description": "India Pale Ale.<em> Escondido, Colo."
}
}
]
},
{
"category": "Wine",
"category_list": [...]
}
]
这可能工作,但我希望它加入类似的键(即:Draft Beer)到相同的数组。当我json_encode($subcategory_data)时,它确实这样做了,如下所示,但它没有被分成类别,只是子类别。
[
{
"subcategory": "Draft Beer",
"subcategory_list": [
{
"id": "1",
"item_name": "Yuengling",
"description": "Lager. Pottstown, Pa."
},
{
"id": "6",
"item_name": "Bud Light",
"description": "American Light Lager. Milwaukee, Wisc."
}
]
},
{
"subcategory": "Red Wine",
"subcategory_list": [
{
"id": "17",
"item_name": "Kendall-Jackson",
"description": "Cabernet Sauvignon, 2010."
},
{
"id": "18",
"item_name": "Sanford",
"description": "Pinot Noir, 2011. Lompoc, Calif"
}
]
},
{
"subcategory": "Domestic Bottles",
"subcategory_list": [
{
"id": "9",
"item_name": "Stone IPA",
"description": "India Pale Ale. Escondido, Colo."
},
{
"id": "10",
"item_name": "Blue Moon",
"description": "Belgian-style Wheat Ale."
}
]
}
]
所以我的问题是为什么它合并在第二组数据而不是第一组数据。如何将subcategory_data转换为category_data。任何帮助我都非常感激。下面是一个例子,如果我正在寻找:
{
"category_name":"Beer",
"category_list" : [
{
"subcategory_name": "Draft Beer",
"subcategory_list": [
{
"id": "1",
"item_name": "Yuengling",
"description": "Lager. Pottstown, Pa."
},
{
"id": "6",
"item_name": "Bud Light",
"description": "American Light Lager. Milwaukee, Wisc."
}
}
]
},
{
"category_name":"Wine",
"category_list" : [
{
"subcategory_name": "Red Wine",
"subcategory_list": [...]
}
]
}
感谢寻找,我是相当新的PHP和我依靠我的javascript技能。
首先,尝试var_dump($categories)
。您将看到您正在构建一个相当奇怪的数据结构(您有一个包含1个元素的数组…)。以下代码将构建一个更简单的结构:
$categories[$row['category']][$row['subcategory']][] = array(
'id' => $row['id'],
'item_name' => $row['item_name'],
'description' => $row['description'],
'price' => $row['price'],
);
这将序列化为JSON,这可能是可以接受的:
{
"Beer": {
"Draft Beer": [
{
"id": "1",
"item_name": "Yuengling",
"description": "Lager. Pottstown, Pa."
},
{
"id": "6",
"item_name": "Bud Light",
"description": "American Light Lager. Milwaukee, Wisc."
}
],
...
一个额外的转换以您要求的格式获取数据:
foreach ($categories as $category_name => $subcategories) {
$subcategory_data = array();
foreach ($subcategories as $subcategory_name => $items) {
$subcategory_data[] = array(
'subcategory_name' => $subcategory_name,
'subcategory_list' => $items
);
}
$category_data[] = array(
'category_name' => $category_name,
'category_items' => $subcategory_data
);
}