在Php - cpp中将Php::Object转换回c++对象 - Convert a Php::Object back to a C++ object in PHP-CPP?

Convert a Php::Object back to a C++ object in PHP-CPP?

本文关键字：Php c++ 对象转换 Object cpp 中将 | 更新日期: 2023-09-27

我试图通过PHP- cpp为PHP做一个Bencode扩展，所以有几个类，如:

class BItem : public Php::Base {
public:
virtual std::string getType() const {
    return "BItem";
}
};
class BDict : public BItem {
public:
std::unordered_map<std::string, BItem*> BData;
std::string getType() const {
    return "BDict";
}
Php::Value getItem(Php::Parameters &params) {
    std::string key = params[0];
    ...
    ...
    return Php::Object(...);
}
// PHP: $a = new BDict(); $b = new BDict(); $a->addItem($b);
void addItem(Php::Parameters &params) {
    std::string key = params[0];
    /**
     * Here's the part confusing me
     * Is there something like:
     */
    BItem *toInsert = &params[1]; // However, params[1] is actually a Php::Object
    BData.insert({key, toInsert});
}
};
class BStr : public BItem {...};
class BList : public BItem {...};
class BInt : public BItem {...};

除BItem外的所有类型都可以插入BDict。

因此，在创建其中一个实例后，我如何将其传递回c++部分，"转换"回c++对象并最终将其插入BData ?

我是php扩展的新手，任何帮助或提示都将非常感谢。

根据Emiel的回答

void myFunction(Php::Parameters &params)
{
    // store the first parameter in a variable
    Php::Value object = params[0];
    // we want to be 100% sure that the passed in parameter is indeed one of our own objects
    if (!object.instanceOf("MySpecialClass")) throw Php::Exception("Wrong parameter passed");
    // cast the PHP object back into a C++ class
    MySpecialClass *cppobject = (MySpecialClass *)object.implementation();
    // @todo add your own code
}