我现在通过PHP echo:
显示javascript echo 'var currentInvoiceDataJSON = <?php echo json_encode($yearData_Invoices[$currentYear] ); ?>;';
然而,我得到一个Uncaught SyntaxError: Unexpected token <我推断这个错误与第二个错误有关>
我怎样才能解决这个问题,还有其他的可能性吗?
我推断这个错误与第二个错误有关>该代码以无效Javascript代码结束。
结果如下:
您的服务器回显字符串:
echo 'var currentInvoiceDataJSON = <?php echo json_encode($yearData_Invoices[$currentYear] ); ?>;';
你的浏览器现在有:
var currentInvoiceDataJSON = <?php echo json_encode($yearData_Invoices[$currentYear] ); ?>;
一旦PHP脚本完成运行并回显第一个字符串,PHP就不能处理内部回显。
我会怎么做:
$data = json_encode($yearData_Invoices[$currentYear]);
echo 'var currentInvoiceDataJSON = ' . $data . ';';
改为:
echo 'var currentInvoiceDataJSON = '.<?php echo json_encode($yearData_Invoices[$currentYear] ); ?>.';';
我还没有测试过这个,但给它一个尝试:
echo "var currentInvoiceDataJSON = '".str_replace("'","'''",json_encode($yearData_Invoices[$currentYear]))."';";
直接改成
echo "var currentInvoiceDataJSON = ".json_encode($yearData_Invoices[$currentYear] ).";";
还要注意PHP中的单引号字符串不会插入变量,所以
$a = "Hello World";
echo '$a'; // outputs : $a
echo "$a"; // outputs : Hello World
和