电子邮件表单发送空白邮件 - Email form sends blank emails

我在我的网站上有一个电子邮件表单，当我试图发送电子邮件时，我收到它，但它是空白的，那里什么也没有。

我是php的新手，所以我对它几乎没有经验。

我一直在寻找解决问题的方法，但没有找到。

请帮助。

这是我的代码:

<form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="sendemail.php">
    <div class="col-sm-5 col-sm-offset-1">
        <div class="form-group">
            <label>Name *</label>
            <input type="text" name="name" class="form-control" required>
        </div>
        <div class="form-group">
            <label>Email *</label>
            <input type="email" name="email" class="form-control" required>
        </div>
        <div class="form-group">
            <label>Phone</label>
            <input type="number" class="form-control">
        </div>
        <div class="form-group">
            <label>Company Name</label>
            <input type="text" class="form-control">
        </div>                        
    </div>
    <div class="col-sm-5">
        <div class="form-group">
            <label>Subject *</label>
            <input type="text" name="subject" class="form-control" required>
        </div>
        <div class="form-group">
            <label>Message *</label>
            <textarea name="message" id="message" required class="form-control" rows="8"></textarea>
        </div>                        
        <div class="form-group">
            <button type="submit" name="submit" class="btn btn-primary btn-lg" required="required">Submit Message</button>
        </div>
    </div>
</form>

PHP文件:

<?php
header('Content-type: application/json');
$status = array(
    'type'=>'success',
    'message'=>'Thank you for contact us. As early as possible  we will contact you '
);
$name = @trim(stripslashes($_POST['name'])); 
$email = @trim(stripslashes($_POST['email'])); 
$subject = @trim(stripslashes($_POST['subject'])); 
$message = @trim(stripslashes($_POST['message'])); 
$email_from = $email;
$email_to = 's.design.mg@gmail.com';//replace with your email
$body = 'Name: ' . $name . "'n'n" . 'Email: ' . $email . "'n'n" . 'Subject: ' . $subject . "'n'n" . 'Message: ' . $message;
$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');
echo json_encode($status);
die;
?>

<?php
$to = "somebody@example.com";
$subject = "HTML email";
$message = "";
// Always set content-type when sending HTML email
$headers = "MIME-Version: 1.0" . "'r'n";
$headers .= "Content-type:text/html;charset=UTF-8" . "'r'n";
// More headers
$headers .= 'From: <webmaster@example.com>' . "'r'n";
$headers .= 'Cc: myboss@example.com' . "'r'n";
mail($to,$subject,$message,$headers);
?>

查看邮件函数，设置变量为pramiter，并删除@。

查看内容....

试试这个

<?php
    header('Content-type: application/json');
    $status = array(
        'type'=>'success',
        'message'=>'Thank you for contact us. As early as possible  we will contact you '
    );
    $name = stripslashes($_POST['name']);
    $email = stripslashes($_POST['email']);
    $subject = stripslashes($_POST['subject']);
    $message = stripslashes($_POST['message']);
    $email_from = $email;
    $email_to = 's.design.mg@gmail.com';//replace with your email
    $body = 'Name: ' . $name . "'n'n" .
        'Email: ' . $email . "'n'n" .
        'Subject: ' . $subject . "'n'n" .
        'Message: ' . $message;
    $header = "MIME-Version: 1.0" . "'r'n";
    $header .= 'From:'.$email_from . "'r'n";
    $success = @mail($email_to, $subject, $body,$header );
    echo json_encode($status);
    die;
?>

，也可以使用escape_string函数