Using PHP how do I test a string for a pattern then alter it?

在PHP中给定这个字符串:

$string = '/sometext?123#abc/moretext';

如何测试模式"是否存在?123#abc/"总是由"?"answers"/"包围，但有不同的内部文本，可以包括任何文本和符号?模式之外的文本也会有所不同。我需要这样做:

if ($string includes pattern ?*/) {
  //load the inner value into a variable
  //then remove the entire patern including the leading "?" and trailing "/" and replace with a single "/"
}

我该怎么做?

<?php
$string = '/sometext?123#abc/moretext';
$pattern = '/''?(.*?)''//';
if( $pieces = preg_split($pattern, $string, Null, PREG_SPLIT_DELIM_CAPTURE)) {
    echo($pieces[1] . "'n");
    unset($pieces[1]);
    echo(implode("/", $pieces) . "'n");
}
?>
--output:--
~/php_programs$ php 1.php 
123#abc
/sometext/moretext

试试这个

$s = '/sometext?123#abc/moretext';
$matches = array();
$t = preg_match('#'?(.*?)'/#s', $s, $matches);
if($matches[1])
   echo "match";
else
   echo "not";

<标题> 输出

match

使用PHP我如何测试一个字符串的模式，然后改变它

Using PHP how do I test a string for a pattern then alter it?

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