Jquery引导模式PHP

您只需要在submit被点击时调用modal。然后，根据用户单击的内容执行ajax调用。

有些像这样:

//Submit Button
<div class="form-group">
    <button id="submit" name="submit" class="btn btn-primary">Submit</button>
</div>
//Modal to ask for confirmation
<div id="confirm" class="modal hide fade">
  <div class="modal-body">
    Are you sure?
  </div>
  <div class="modal-footer">
    <button type="button" data-dismiss="modal" class="btn btn-primary" id="yes">Yes</button>
    <button type="button" data-dismiss="modal" class="btn" id="no">No</button>
  </div>
</div>

然后，您只需要为每个按钮添加侦听器并执行相应的操作。

<script type="text/javascript">
    //If user submits, show modal.
    $("#submit").click(function() {
        showModal();
    });
    //If user selects Yes, do action A.
    $("#yes").click(function() {
        doAjax_A();
    });
    //If user selects No, do action B.
    $("#no").click(function() {
        doAjax_B();
    });
</script>