我有两个数组。我们称它们为member_ids和member_names
所以第一个数组(member_ids)看起来像:
Array
(
[0] => 572149922960422
[1] => 1586735531587728
[2] => 1084479334908663
[3] => 9875443331682
[4] => 9291002010388
[5] => 2108382717199939
[6] => 911647002295982
[7] => 100222991929377
)
第二个数组(member_names)看起来像
Array
(
[0] => John Doe
[1] => Jane Doe
[2] => Shawn Smith
[3] => Jack Nickleson
[4] => Brad Pitt
[5] => Chad Kroger
[6] => Angelina Jolie
[7] => Bruce Campell
)
最重要的是，即使变量可以不同，迭代也总是相互匹配(这意味着member_id[0]是member_name[0]的成员ID，等等)。但是我想创建一个名为member_info的多维，它使用来自两个数组的数据，所以新的URL(如果您从两个数组中获取数据)看起来像这样:
Array
(
[0] => Array
(
[member_id] => 572149922960422
[member_name] => John Doe
)
[1] => Array
(
[member_id] => 1586735531587728
[member_name] => Jane Doe
)
[2] => Array
(
[member_id] => 1084479334908663
[member_name] => Shawn Smith
)
[3] => Array
(
[member_id] => 9875443331682
[member_name] => Jack Nickleson
)
[4] => Array
(
[member_id] => 9291002010388
[member_name] => Brad Pitt
)
[5] => Array
(
[member_id] => 2108382717199939
[member_name] => Chad Kroger
)
[6] => Array
(
[member_id] => 911647002295982
[member_name] => Angelina Jolie
)
[7] => Array
(
[member_id] => 100222991929377
[member_name] => Bruce Campell
)
)
请记住，两个数组都是不同的，因此两个数组的id和name的变量将取决于数据库。这只是我想要实现的一个例子。
你可以这样做:
<?php
$ids = [
572149922960422,
1586735531587728,
1084479334908663,
9875443331682,
9291002010388,
2108382717199939,
911647002295982,
100222991929377
];
$names = [
"John Doe",
"Jane Doe",
"Shawn Smith",
"Jack Nickleson",
"Brad Pitt",
"Chad Kroger",
"Angelina Jolie",
"Bruce Campell"
];
function customCombine($combined){
$final = [];
$i = 0;
foreach($combined as $id => $name){
$final[$i]['member_id'] = $id;
$final[$i]['member_name'] = $name;
$i++;
}
return $final;
}
print_r(customCombine(array_combine($ids,$names)));
您可以在这里看到结果