在编码器中连接两个数据库不工作


Connecting two database in codeigniter not working

我正在尝试连接Codeigniter中的两个数据库。我遇到了这个链接Codeigniter -多个数据库连接,并根据我的要求设置数据库。现在的问题是只有默认数据库是活动的。下面是代码

模型

function __construct()
    {
        parent::__construct();
        $this->db_2 = $this->load->database('database2', TRUE);
        $this->load->database();
    }
function get_details()
    { 
        $result1 = $this->db->query("select columnname1 from tablename")->result();
        $result2 = $this->db_2->query("select columnname2 from tablename")->result();
    }

我得到一个错误,因为columnname2只存在于database2表,而不存在于database1表。
Error: Unknown column 'columnname2' in 'field list'

Database.php

$db['database2']['hostname'] = 'localhost';
$db['database2']['username'] = 'root';
$db['database2']['password'] = '';
$db['database2']['database'] = 'database2';
$db['database2']['dbdriver'] = 'mysql';
$db['database2']['dbprefix'] = '';
$db['database2']['pconnect'] = TRUE;
$db['database2']['db_debug'] = TRUE;
$db['database2']['cache_on'] = FALSE;
$db['database2']['cachedir'] = '';
$db['database2']['char_set'] = 'utf8';
$db['database2']['dbcollat'] = 'utf8_general_ci';
$db['database2']['swap_pre'] = '';
$db['database2']['autoinit'] = TRUE;
$db['database2']['stricton'] = FALSE;
$active_group = 'default';
$active_record = TRUE;
$db['default']['hostname'] = 'localhost';
$db['default']['username'] = 'root';
$db['default']['password'] = '';
$db['default']['database'] = 'database1';
$db['default']['dbdriver'] = 'mysql';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;

UPDATE:如果我使用下面的

function __construct()
    {   
        parent::__construct();
        $this->load->database();
        $this->db_2 = $this->load->database('database2', TRUE);    
    }

database2被CI视为活动的,即使使用$this->db->query();指定查询,所有查询也连接到数据库2。

在构造函数中调用这两个数据库实例将导致其中一个覆盖另一个。解决这个问题最简单的方法是拆分你的函数并将它们合并在一起。

function __construct() {
    $this->load->database('default', true);
}
function merge_results() {
    $result_a = $this->get_result_a();
    $result_b = $this->get_result_b();
    return array_merge($result_a,$result_b);
}
function get_result_a() {
    return $this->db->query("select columnname1 from tablename")->result();
}
function get_result_b() {
    $other_db = $this->load->database('db2',true);
    return $other_db->query("select columnname2 from tablename")->result();
}