将数组从最后一个排序到第一个 - sort an array last to first

sort an array last to first

我有一个数组，现在我想按升序对数组进行排序。我试过了，但没有用。数组是

   Array
    (
        [0] => Array
            (
                [0] => 216
                [id] => 216
                [1] => 52.42
                [TRUNCATE(100*(sum(m.carbs/(m.carbs+m.fat+m.protein))/count(u.id)),2)] => 52.42
                [2] => 2014-07-22
                [Cdate] => 2014-07-22
            )
        [1] => Array
            (
                [0] => 217
                [id] => 217
                [1] => 73.91
                [TRUNCATE(100*(sum(m.carbs/(m.carbs+m.fat+m.protein))/count(u.id)),2)] => 73.91
                [2] => 2014-07-19
                [Cdate] => 2014-07-19 
            )
        [2] => Array
            (
                [0] => 220
                [id] => 220
                [1] => 71.87
                [TRUNCATE(100*(sum(m.carbs/(m.carbs+m.fat+m.protein))/count(u.id)),2)] => 71.87
                [2] => 2014-07-18
                [Cdate] => 2014-07-18
            )

现在我想排序我的数组从最后到第一个索引

2 1 0

我已经写了函数，但没有工作

function lastSort($a, $b) {
    $aLast = end(explode(' ', $a));
    $bLast = end(explode(' ', $b));
    return strcasecmp($aLast, $bLast);
}
$r=uasort($array, 'lastSort');diamen

因为你想要反转一个数组，为什么不使用PHP的原生函数array_reverse呢?

$array = array(/*... Your array*/);
$r = array_reverse($array);

这将节省你:array_reverse()。

使用array_reverse http://php.net/manual/en/function.array-reverse.php

<?php
$array = array(0 => array("foo" => "bar"),
               1 => array("faz" => "baz"),
               2 => array("x" => "y")
              );
print_r( array_reverse($array, true) );

结果为:

Array
(
    [2] => Array
        (
            [x] => y
        )
    [1] => Array
        (
            [faz] => baz
        )
    [0] => Array
        (
            [foo] => bar
        )
)