我试图在php中创建一个函数，将从数组中读取。我正在尝试连接文本和数组id号，读取数组中的值，但是它是正在返回的连接文本，而不是数组的值。
下面是我的代码://arrays with words in dictionary
$dictionary_word1 = array("test1","test2","test3");
$dictionary_word2 = array("test4","test5","test6");
$dictionary_word3 = array("test7","test8","test9");
$word_to_lookup = "dictionary_word_1";
//value to send to function
$returned_word = convert_word($word_to_lookup);
//value returned from function
echo "<br>the returned word from the function is " . $returned_word;
//the text "$dictionary_word_1[2]" is displayed instead of array value
echo "<br>the value in the array is " . $dictionary_word1[2];
//this displays correcty as "test3"
function convert_word($word_to_convert)
{
global $dictionary_word1;
$converted_word = '$'.$word_to_convert .'[2]';
return $converted_word;
}
谁能给我任何提示，我在哪里做错了?
您需要以这种方式引用变量来执行您正在尝试的操作(参见PHP:变量变量和PHP:变量解析):
$converted_word = ${$word_to_convert}[2];
但是，注意到dictionary_word_1和$dictionary_word1之间的区别吗?行不通的。
无论如何，当你这样做的时候，你最好使用数组。在本例中是一个多维数组。考虑:
$words[1] = array("test1","test2","test3");
$words[2] = array("test4","test5","test6");
$words[3] = array("test7","test8","test9");
你总是使用$words只是改变索引然后从数组中使用一个词