有条件地组合PHP数组 - Conditionally Combine PHP Array

Conditionally Combine PHP Array

本文关键字：数组 PHP 组合有条件 | 更新日期: 2023-09-27

是否有一个干净的方式来组合2 PHP数组有条件?我分别从两个数组中获得以下JSON-Response:

数组1:

[
      {
        "field": {
          "id": 20,
          "name": "Erfolge",
          "field-id": "erfolge",
          "type": "textarea"
        }
      },
      {
        "field": {
          "id": 29,
          "name": "Sprachen",
          "field-id": "sprachen",
          "type": "text"
        }
      }
]

第二个数组:

    [
  {
    "field": {
      "id": 20,
      "name": "Erfolge",
      "field-id": "erfolge",
      "type": "textarea"
    },
    "value": "new entry"
  },
  {
    "field": {
      "id": 4,
      "name": "Trikotnummer",
      "field-id": "trikotnummer",
      "type": "number"
    },
    "value": "test"
  },
  {
    "field": {
      "id": 29,
      "name": "Sprachen",
      "field-id": "sprachen",
      "type": "text"
    },
    "value": "Text"
  }
]

我想要以下目标输出:

    [
      {
        "field": {
          "id": 20,
          "name": "Erfolge",
          "field-id": "erfolge",
          "type": "textarea"
        },
        value: "new entry"
      },
      {
        "field": {
          "id": 29,
          "name": "Sprachen",
          "field-id": "sprachen",
          "type": "text"
        },
        value: "Text"
      }
]

这意味着只有当字段存在于第一个数组中时，它才必须添加值。我当前的解决方案给出了所有没有正确映射的字段:

$fieldData = array();
    foreach ($fields as $field) {
        $fieldData[]['fields'] = $field->getArrayCopy();
    }
    // Get Values
    $values = $user->getProfileFieldValue();
    $fieldValue = array();
    foreach ($values as $value) {
        $fieldValue[] = $value->getArrayCopy();
    }
    $result = array_merge($fieldData, $fieldValue);

我应该使用函数array_walk吗?

这是一种开销很大的方法，它会在第二个数组中查找与第一个数组ID匹配的元素。

$result = array();
foreach ($first as $e1) {
    $id = $e1['field']['id'];
    foreach ($secondArray as $e2) {
        if ($e2['field']['id'] == $id) {
            $e1['value'] = $e2['value'];
            break;
        }
    }
    $result[] = $e1;
}

如果第二个数组非常大，您可以通过首先创建一个关联数组来优化它，该关联数组的键是第二个数组中的id，值是值。

https://secure.php.net/manual/en/function.array-uintersect.php

$res = array_uintersect($arr1, $arr2, function($a, $b){
  return $a['field']['id'] - $b['field']['id'];
});