PHP:从For循环中获取多个变量值 - PHP: Getting Multiple Variable Values From For Looping

PHP: Getting Multiple Variable Values From For Looping

本文关键字：获取变量值循环 For PHP | 更新日期: 2023-09-27

这是我的另一个问题，这是我的代码

for($d = 0; $d < $cnt; $d++){
                $fetchit = mysql_query("SELECT * FROM ar_subkategori WHERE id_subkategori = $detail_sub[$d]");
                $datafetch = mysql_fetch_array($fetchit);
                $id_values = $datafetch['id_subkategori'];
                if ($id_values == $getsubsel['id_subkategori']){
                    echo "<input type='checkbox' name='checkbox[]' id='checkbox' value='$getsubsel[id_subkategori]' checked> <span style='font-size:10px; color:#FFA412;'>[ID: $getsubsel[id_subkategori]]</span> $getsubsel[nama_subkategori] <span style='color:#FFA412; font-style:italic; font-size:12px;'>*Ini adalah sub dari ID: $getsubsel[id_subkategori_induk]</span></br>";
                }               
            }
            if ($id_values != $getsubsel['id_subkategori']){
                echo "<input type='checkbox' name='checkbox[]' id='checkbox' value='$getsubsel[id_subkategori]'> <span style='font-size:10px; color:#FFA412;'>[ID: $getsubsel[id_subkategori]]</span> $getsubsel[nama_subkategori] <span style='color:#FFA412; font-style:italic; font-size:12px;'>*Ini adalah sub dari ID: $getsubsel[id_subkategori_induk]</span></br>";
            }

问题是form $id_values的值总是show ID = 30，而show的值应该是1,5,10,30。如何解决这个问题?

谢谢你，萨拉姆。

如果你想要一个数组变量显示在"里面，你必须像这样用{}包围它:

"{$getsubsel['id_subkategori']}"

可能是…

$fetchit = mysql_query("SELECT * FROM ar_subkategori WHERE id_subkategori = $detail_sub[" . strval($d) . "]");

或

$fetchit = mysql_query("SELECT * FROM ar_subkategori WHERE id_subkategori = $detail_sub['{$d}']");

试试

 $fetchit = mysql_query("SELECT * FROM ar_subkategori WHERE id_subkategori = '".$detail_sub[$d]."'");