下面的代码应该搜索数据库。但我得到错误，我的表不存在。我还想问为什么如果我按第二次提交按钮，它只是跳转到else，所以它返回choose at least.... and also all data from database.。谢谢!
php
if (isset($_POST['submit'])) {
$query = 'SELECT * FROM station_tab';
if (!empty($_POST['station_name']) && !empty($_POST['city']) && !empty($_POST['zone']))
{
$query .= 'WHERE station_name' .mysql_real_escape_string($_POST['station_name']) . 'AND city' . mysql_real_escape_string($_POST['city']) . 'AND zone' . mysql_real_escape_string($_POST['zone']);
} elseif (!empty($_POST['station_name'])) {
$query .= 'WHERE station_name' . mysql_real_escape_string($_POST['station_name']);
} elseif (!empty($_POST['city'])) {
$query .= 'WHERE city' . mysql_real_escape_string($_POST['city']);
} elseif (!empty($_POST['zone'])) {
$query .= 'WHERE zone' . mysql_real_escape_string($_POST['zone']);
} else {
echo "Choose at least one option for search";
}
$result = mysql_query($query, $db) or die(mysql_error($db));
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)){
echo '<br/><em>' .$row['station_name'] . '</em>';
echo '<br/>city: '. $row['city'];
echo '<br/> zone: ' .$row['zone'];
echo '<br/> Long: ' .$row['lon'];
echo '<br/> Lat: ' . $row['lat'];
}
}
}
当我添加城市名称到城市时，这里是错误消息。
Table 'stanice_tab.station_tabwhere' doesn't exist
更正后的代码:
$query = 'SELECT * FROM station_tab '; // note the space at the end
if (!empty($_POST['station_name']) && !empty($_POST['city']) && !empty($_POST['zone'])) {
$query .= ' WHERE station_name = "' .mysql_real_escape_string($_POST['station_name']) . '" AND city = "' . mysql_real_escape_string($_POST['city']) . '" AND zone = "' . mysql_real_escape_string($_POST['zone']).'"'; // note the = signs and the space before each AND
} elseif (!empty($_POST['station_name'])) {
$query .= ' WHERE station_name = "' . mysql_real_escape_string($_POST['station_name']).'"'; // note the = sign and the space at the beginning
} elseif (!empty($_POST['city'])) {
$query .= ' WHERE city = "' . mysql_real_escape_string($_POST['city']).'"'; // note the = sign and the space at the beginning
} elseif (!empty($_POST['zone'])) {
$query .= ' WHERE zone = "' . mysql_real_escape_string($_POST['zone']).'"'; // note the = sign and the space at the beginning
} else {
echo "Choose at least one option for search";
}
采取echo的习惯，你的$query变量，这样连接不会增加任何打字错误。
in phpmyadmin select database and then select your table
和上面的菜单中有一个SQL菜单。您可以使用此功能来构建SQL查询或在出现以下错误时进行调试