从数据库字段中抓取链接，并使用它将我抓取的另一个字段转换为链接

我有一个电影语录网站。我有一些php和javascript是我付钱给别人写的，我对php和javascript一无所知。代码从数据库中获取随机引用，并将其显示在站点上。它每10秒换一次报价。我也有一个字段在数据库中称为链接，其中包含链接到电影页面，报价是从。我想把这句话变成那个电影页面的链接。我将感谢任何帮助如何改变代码来做到这一点。

randomquote.php文件:

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "dbname";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
header("Content-Type: text/xml; charset=utf-8");
header("Expires: Mon, 26 Jul 1997 05:00:00 GMT" );
header("Last-Modified: " . gmdate( "D, d M Y H:i:s" ) . "GMT" );
header("Cache-Control: no-cache, must-revalidate" );
header("Pragma: no-cache" );
$sql = "SELECT COUNT(*) FROM quotes";
$result = mysqli_query($conn,$sql);
$rows=$result->fetch_row();
//$rows = mysqli_num_rows($result);
$rndm=rand(1,$rows[0]);
$sql = "SELECT quote FROM quotes where id='".$rndm."' Limit 1";
$result = mysqli_query($conn,$sql);
if($result)
{
$row = mysqli_fetch_assoc($result);
$xml='<root>';
$xml.='<qoute>'.htmlspecialchars($row['quote']).'</qoute>';
$xml.='</root>';
echo $xml;
}
else
{
echo "Not working";
}
mysqli_close($conn);
?>

var qouteobj=createRequestObject();
function getqoute(){
qouteobj.open("GET","/php/randomquote.php",true);
qouteobj.send(null);
qouteobj.onreadystatechange=function(){
if(qouteobj.readyState==4 && qouteobj.status==200)
{
var q_rec=qouteobj.responseText;
if (window.DOMParser)
{
parser=new DOMParser();
xmlDoc=parser.parseFromString(q_rec,"text/xml");
}
else // Internet Explorer
{
xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async=false;
xmlDoc.loadXML(q_rec);
}
var rq=xmlDoc.getElementsByTagName("qoute");
var txt="";
var i;
for (i=0;i<rq.length;i++){
txt=txt + rq[i].childNodes[0].nodeValue + "<br>";
}
document.getElementById('random-quote').innerHTML=txt;
setTimeout('getqoute()',10000);
}
}
}