如何将两个查询数据包含到单个结果中 - How to include the 2 query data into single result?

How to include the 2 query data into single result?

我有两个这样的查询

查询1

        $this->db->select('*');
    $this->db->from('transaction_log');
    $this->db->join('crs_hotel_booking_details', 'transaction_log.app_reference = crs_hotel_booking_details.app_reference');
    $this->db->join('crs_hotel_supplier_details', 'crs_hotel_booking_details.hotel_id = crs_hotel_supplier_details.hotel_id');
    $this->db->join('crs_supplier_login', 'crs_supplier_login.supplier_id = crs_hotel_supplier_details.supplier_id');
    $this->db->where('crs_supplier_login.supplier_id',$this->entity_user_id);
    $query = $this->db->get();

查询2

    $this->db->select('*');
    $this->db->from('transaction_log');
    $this->db->join('service_booking_details', 'transaction_log.app_reference = service_booking_details.app_reference');
    $this->db->join('crs_service_supplier_details', 'service_booking_details.service_apartment_id = crs_service_supplier_details.service_apartment_id');
    $this->db->join('crs_supplier_login', 'crs_supplier_login.supplier_id = crs_service_supplier_details.supplier_id');
    $this->db->where('crs_supplier_login.supplier_id',$this->entity_user_id);
    $query = $this->db->get();

我得到了两个查询的值。请告诉我如何添加这两个查询

就像，

array_merge($query1->result_array(), $query2->result_array());

SQL有UNION子句，它从两个或多个SELECT语句返回单个结果集。