我是一个PHP新手,我不能在PHP中显示图像数据。我试了1个小时,但不能理解这个问题。请帮助。
<?php
ini_set('mysql.connect_timeout',300);
ini_set('default_socket_timeout',300);
?>
<form method="post" enctype="multipart/form-data">
<br/>
<input type="file" name="image"/>
<br/><br/>
<input type="submit" name="submit" value="Upload"/>
</form>
<?php
if(isset($_POST['submit'])
{
$imagedata=mysql_real_escape_string(file_get_contents($_FILES["image"],["tmp_name"]));
echo $imagedata;
}
else
{
echo "there has been some error";
}
?>
</body>
修复代码:
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="image">
<input type="submit" name="submit" value="Upload">
</form>
<?php
if(isset($_POST['submit'])) {
$imagedata=file_get_contents($_FILES["image"]["tmp_name"]);
echo $imagedata;
} else {
echo "there has been some error";
}
?>
</body>
</html>
然而,这只会输出二进制数据。如果你想实际显示图像,你需要做更多的事情。