我想将text-decoration:line-through应用到一个表行,这将按照mysql查询循环。只有当变量的值不感兴趣
时,我才想去掉行 在下面的循环中,有一个id为line的表行。还有一个变量$status。我希望标签行得到剔除,如果$status的值来"不感兴趣",我怎么能做到这一点?
while ($prow=mysql_fetch_object($productname))
{
$pname.=$prow->name.'<br />';
}
$staffname=mysql_query("select name from staff where sid='$assignedto' or flag='$assignedto'");
if(mysql_num_rows($staffname) > 1)
{
echo "<tr id='line'";
if($count %2==0)
echo "bgcolor='white' style='height:10px;'";
echo ">";
$count++;
?>
<td>
<span class="time"><a title="<?echo $added;?>" ></a></span>
</td>
<?
echo "<td >".$name. "</td>";
echo "<td>".$status."</td>";
echo "<td >".$phone." "."|"." ".$mobile. "</td>";
// echo "<td >".$email. "</td>";
echo "<td >".$city. "</td>";
echo "<td >".$pname. "</td>";
echo "<td >".$sname. "</td>";
echo "<td >".$lastactivity. "</td>";
?>
</table>
像这样:
if ($status == 'Not Interested') { $strike = 'text-decoration:line-through'; }
else { $strike = ''; }
然后
echo "<tr id='line'";
if($count %2==0)
echo "bgcolor='white' style='height:10px; $strike'";
echo ">";
如果$status不是'Not Interested'
,它将简单地添加''
而不是text-decoration:line-through
在循环中,您可以检查$status的值,如果它匹配"Not Interested",您只需向该行添加一个特定的CSS类(例如:class="line-through"),然后像这样在CSS中处理其余的内容:
tr.line-through td{
text-decoration:line-through
}