如何设置没有MySQL数据的分页

我的任务是以文件夹的名称及其在服务器上的位置开始列出数据(产品详细信息)。MySQL没有被使用，不幸的是它不在我的手中，这给我带来了分页问题…如有任何帮助，我将不胜感激。

这是我的代码…虽然很丑，但效果很好……只是它会显示所有结果!

<div style="width:750px;">
<?php
$ALL_PARTS = array();
// LOOP THROUGH MEMBERS RESOURCES ROOT FOLDER TO FIND ALL MEMBER RESOURCES FOLDERS
foreach (glob("root_folder/sub_folder/*",GLOB_ONLYDIR) as $ROOT_FOLDERS_PATH) {
// WE CAN NOW FIND ALL RELEVANT FOLDERS CONTAINING THE DATA NEEDED
       foreach (glob("$ROOT_FOLDERS_PATH/offers/*",GLOB_ONLYDIR) as $RESOURCE_FOLDERS_PATH) {
           $FIXED_PRODUCT_CODE = file_get_contents("$RESOURCE_FOLDERS_PATH/fixed-product-code.txt", true);
           $PRODUCT_TITLE = file_get_contents("$RESOURCE_FOLDERS_PATH/product-title.txt", true);
           $PRODUCT_DESCRIPTION = file_get_contents("$RESOURCE_FOLDERS_PATH/product-description.txt", true);
// WE NOW NEED TO RETURN THE PRODUCT IMAGE NAME WHICH IS IN ANOTHER LOCATION
// FIRST CREATE ARRAY OF ITEMS TO FILTER OUT IN RESULT
$ignore = Array(".", "..", "$RESOURCE_FOLDERS_PATH/assets/product_img/index.php", "$RESOURCE_FOLDERS_PATH/assets/product_img/.htaccess");
// GO GET THE IMAGE NAME AND PATH
foreach (glob("$RESOURCE_FOLDERS_PATH/assets/product_img/*") as $GET_IMAGE_NAME) {
// IF WE HAVE AN IMAGE AND PRODUCT CODE, DEFINE OPENING WRAPPER DIV AND THE IMAGE
// THEN DEFINE THE URL TO THE PRODUCT AND CLOSE THE WRAPPER DIV
     if((!in_array($GET_IMAGE_NAME, $ignore)) && (!empty($GET_IMAGE_NAME)) && (!empty($FIXED_PRODUCT_CODE)) ){
         $PART_1 = "<div style='width:355px; margin:0 0 20px 0; padding:10px; float:left; height:130px;'>";
         $PART_2 = "<div style='float:left; height:150px; padding-right:10px;'><img src='" . $GET_IMAGE_NAME . "' width='100' alt='' /></div>";
         $PART_3 = "<div><a href='subscriber_offers.php?product=" . md5($FIXED_PRODUCT_CODE) ."'>" . $PRODUCT_TITLE ."</a><p>" . $PRODUCT_DESCRIPTION  . "</p></div>";
         $PART_4 = "</div>";
     }
}
// PUT DEFINED PARTS TOGETHER 
$ALL_PARTS[$PRODUCT_TITLE] = $PART_1 . $PART_2 . $PART_3 . $PART_4;
    }
}
ksort($ALL_PARTS);
foreach($ALL_PARTS as $PRODUCT){
echo $PRODUCT;
}
?>
</div>

这给了我一个按字母顺序排列的产品列表。

    ksort($ALL_PARTS);
    foreach($ALL_PARTS as $PRODUCT){
    echo $PRODUCT;
}

但是我如何让$arr包含$ALL_PARTS数组的所有数据，这样可以通过分页脚本访问的方式?

下面的代码将给出相关循环的最后一次迭代…(显然)

$arr = array($PRODUCT);