我正在用html, php和javascript制作社交媒体。现在我实现了一个like函数，所以当你点击like按钮时它会转到一个php函数，它会添加一个like。但是当php函数指向post页面时，它指向页面的顶部。是否有一种可能的方法可以引用回喜欢的帖子?
谢谢!
正如Dagon所说，使用AJAX(最好是jQuery AJAX，使您更容易)将是最好的选择。下面是一小段代码:
like.php (POST):
<?php
include 'DatabaseConn.php'; //File that contains the database bridge, let's pretend $bridge is the bridge
if ( !isset($_SESSION['userid'] ) // We verify the user is logged in, by making sure we can access his user ID
$error[] = 'Not logged in';
if ( !isset($_POST['post_id'] ) ) // We verify that a post ID was provided
$error[] = 'Error, no post ID was provided';
if ( !isset($error) )
{
$query = $bridge->query("SELECT * FROM posts WHERE post_id = '".$_POST['post_id']."' LIMIT 1"); //Assuming you're using MySQLi
//I'm going to pretend that there's a column called LIKERS and that each liker is separated by two colons
$data = $query->fetch_array(MYSQLI_ASSOC);
$likers = explode("::", $data['likers']);
$likers_str = $data['likers']; //We'll use this later
if ( $query->num_rows < 1 ) // We make sure the post exists
{
echo json_encode(array("success" => false, "errors" => "The specified post does not exist"));
}
else
{
if ( in_array($_SESSION['userid'], $likers) ) //We find out if the user has liked the post already
{
echo json_encode(array("success" => false, "errors" => "You have already liked this post"));
}
else
{
$query = $bridge->query("UPDATE posts SET likes += 1 WHERE post_id = '".$_POST['post_id']."' LIMIT 1"); // Add the like
$query2 = $bridge->query("UPDATE posts SET likers = '".$likers_str."::".$_SESSION['userid']."' WHERE post_id = '".$_POST['post_id']."' LIMIT 1"); // Add users to likers list
if ( $query && $query2 ) //We verify both queries were successful
echo json_encode(array("success" => true, "errors" => null));
else
echo json_encode(array("success" => false, "errors" => "There has been an error while liking this post"));
}
}
}
else
{
echo json_encode(array("success" => false, "errors" => implode(", ", $error)));
}
like.js (AJAX):
$(document).ready(function() //Assuming you use jQuery
{
$(".likeButton").on('click', function() //Click on like button
{
$.ajax({
method: "POST",
url: "like.php",
data: { post_id : $(this).attr('id') }, //We grab the post id from the button
dataType: "json"
})
.done(function( data ) {
if ( data.success == "true" )
alert('Post liked');
else
alert('Error, could not like post: ' + data.errors);
});
//After executing it I'd recommend disabling the button
})
});
然后，如果你对如何创建按钮感到好奇，它应该这样创建:
<div class="likeButton" id="postid, something like 39128535">Like</div>
祝你项目顺利。
当然，当你点击"喜欢"按钮时，传递一个GET参数(like.php?liked=#id1)，然后，在url的末尾使用id重定向返回:
$hash = $_GET['liked'];
header("Location: where/likes/are.php{$hash}");
#id1应该是一个元素的DOM id，你希望你的页面在哪里滚动。
注意，这只是一个粗略的例子。但是我强烈建议使用AJAX来执行这类过程。