我使用以下代码将json代码转换为数组并将值插入mysql。首先,我使用for循环创建如下表:
$url='http://www.coinchoose.com/api.php';
$contents = file_get_contents($url);
$contents = utf8_encode($contents);
$results = json_decode($contents, true);
for ($i=0; $i<=22; $i++){
mysql_query("CREATE TABLE $symbol(
id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id), timestamp BIGINT, symbol VARCHAR(3), name VARCHAR(20), algo VARCHAR(20), currentBlocks VARCHAR(20), difficulty DECIMAL (18,9), reward DECIMAL (18,9), price DECIMAL (18,9), exchange VARCHAR(20), ratio DECIMAL (8,4))")
or die(mysql_error());
}
然后我使用另一个for循环从http://www.coinchoose.com/api.php的json api插入值到mysql表,如下所示:
$url='http://www.coinchoose.com/api.php';
$contents = file_get_contents($url);
$contents = utf8_encode($contents);
$results = json_decode($contents, true);
print_r($results);
$time=time();
for ($i=0; $i<=22; $i++){
$symbol=strtolower($results[$i]['symbol']);
$name=$results[$i]['name'];
$algo=$results[$i]['algo'];
$currentBlocks=$results[$i]['currentBlocks'];
$difficulty=$results[$i]['difficulty'];
$reward=$results[$i]['reward'];
$price=$results[$i]['price'];
$exchange=$results[$i]['exchange'];
$ratio=$results[$i]['ratio'];
mysql_query("INSERT INTO $symbol VALUES (id, $time, '$symbol', '$name', '$algo', '$currentBlocks', $difficulty, '$reward', $price, '$exchange', $ratio)") or die(mysql_error());
}
我收到以下错误,我不明白:
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 45
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 46
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 47
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 48
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 49
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 50
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 51
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 52
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
( ! ) Notice: Undefined offset: 21 in C:'wamp'www'api.php on line 53
Call Stack
# Time Memory Function Location
1 0.0004 706424 {main}( ) ..'api.php:0
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VALUES (id, 1369998276, '', '', '', '', , '', , '', )' at line 1
我希望有人能澄清为什么我得到这个错误。任何建议,以更好的代码以上,因为我相信它可以在一个更漂亮/更好的方式完成非常感谢。代码确实工作,因为值被解析成mysql!然而,错误仍然出现
for循环条件错误。
for ($i = 0; $i < 22; $i++ ) { // Notice the `<` and not `<=`
或者,如注释所建议的:
for ($i = 0; $i < count($result); $i++ ) {
在$results = json_decode($contents, true);
之后插入$numcount = count($results);
,而不是for ($i=0; $i<=22; $i++){
,您应该像这样插入变量:for ($i=0; $i<$numcount; $i++){